Part A
The small red arcs indicate that angles PQS and RQS are congruent.
13x - 1 = 2(6x + 4)
13x - 1 = 12x + 8
x = 9
m<PQR = 13x - 1 = 116
m<RQS = 6x + 4 = 6(9) + 4 = 58
m<PQS = 116 - 58 = 58
Part B
12^2 + (OH)^2 = 13^2
144 + (OH)^2 = 169
(OH)^2 = 25
OH = 5
r = OH = 5
Part C
WZ/ZY = WX/XY
24/12 = 30/XY
2 = 30/XY
2(XY) = 30
XY = 15
Answer:
c. 105 yd^2.
Step-by-step explanation:
First find the slant height (h) of each of the triangular walls:
tan 60 = h / 3.1
h = 3.1 tan 60
= 5.369 yds.
Area of each side = 3.1* 5.369
= 16.645
Total surface area of the pyramid
= 4 * 16.645 + 6.2^2
= 105.02 yd^2.
Answer:
11.45
Step-by-step explanation:
the circumference is 36 so divide it by pie then rounded it to the nearest hundredths place
Answer: D Step-by-step explanation:
Answer:1:00
Step-by-step explanation:mark me as brainliest
