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2 years ago

Alan removed fish from his pond each day for days. What was the total change in the number of fish in the pond?

Mathematics

2 answers:

BigorU [14]2 years ago

7 0

Answer:

Step-by-step explanation:

um need more info

lbvjy [14]2 years ago

6 0

There is less fish each day

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jimmy is moving to a new apartment. he fills a box with 4 books, 5 DVDs, and 2 CD's. when he starts unpacking his new place he p

pav-90 [236]

Answer:

$\frac{2}{11}$

Step-by-step explanation:

First, find the probability of him pulling out a book.

There are 11 objects in total, and there are 4 books.

So, the probability of pulling out a book is $\frac{4}{11}$

Next, find the probability of him pulling out a DVD after.

Since a book was taken out, there are only 10 objects left. There are 5 DVDs.

So, the probability of pulling out a DVD is $\frac{5}{10}$ , or simplified to $\frac{1}{2}$

To find the probability that this happens in order, multiply the probabilities:

$\frac{4}{11}$ x $\frac{1}{2}$

= $\frac{2}{11}$

So, the probability is $\frac{2}{11}$

7 0

2 years ago

There are 4 people at a party. Consider the random variable X=’number of people having the same birthday ’ (match only month, N=

yulyashka [42]

Answer:

S = {0,2,3,4}

P(X=0) = 0.573 , P(X=2) = 0.401 , P(x=3) = 0.025, P(X=4) = 0.001

Mean = 0.879

Standard Deviation = 1.033

Step-by-step explanation:

Let the number of people having same birth month be = x

The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)

The number of ways of distributing their birthdays = 12⁴

The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)

P(X = 0) = $\frac{12P4}{12^{4} }$

P(X=0) = 0.573

P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)

P(X=2) = $\frac{3C2 * 12P2}{12^{4} } + \frac{4C2 * 12P3}{12^{4} }$

P(X=2) = 0.401

P(X=3) = $\frac{4C3 * 12P2}{12^{4} }$

P(x=3) = 0.025

P(X=4) = $\frac{12}{12^{4} }$

P(X=4) = 0.001

Mean, $\mu = \sum xP(x)$

$\mu = (0*0.573) + (2*0.401) + (3*0.025) + (4*0.001)\\\mu = 0.879$

Standard deviation, $SD = \sqrt{\sum x^{2} P(x) - \mu^{2}} \\SD =\sqrt{ [ (0^{2} * 0.573) + (2^{2} * 0.401) + (3^{2} * 0.025) + (4^{2} * 0.001)] - 0.879^{2}}$

SD = 1.033

4 0

3 years ago

Solve the quadratic function by factoring. You must fill in

Stells [14]

Answer:

5x+2=0

Step-by-step explanation:

When factoring you add or subtract your factors that are similar.

For example 9x-4x+ 5x

and this is how you get 5x+2=0

Any Questions?

4 0

2 years ago

Read 2 more answers

Please help me answer this

Ronch [10]

Answer:

10.77

Step-by-step explanation:

by using Pythagoras theorem we can find the distance between the points,

so...

distance between the points, which is the hypotenuse will be xy

difference between the y coordinates will be dy

difference between the x coordinates will be dx

according to pythagoras theorem,

$xy^{2} = dx^{2} + dy^{2} \\xy^{2} = (-6-(-2))^{2} + (-5-5)^{2}\\xy^{2} =(-4)^{2} +(-10)^{2} \\xy^{2} =16+100\\xy^{2} =116\\xy =\sqrt{116} \\xy=10.77$

8 0

2 years ago

Help please I will give brainliest ❤

Maslowich

Step-by-step explanation:

a < (a + b)/2 < b

Solve the first inequality.

a < (a + b)/2

2a < a + b

a < b

Solve the second inequality.

(a + b)/2 < b

a + b < 2b

a < b

Both inequalities are true. Therefore, a < (a + b)/2 < b.

6 0

3 years ago

Read 2 more answers