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3 years ago

Answer It, Thanks. -3(-100)

Mathematics

2 answers:

Kaylis [27]3 years ago

6 0

Answer: 300

Step-by-step explanation:

Anettt [7]3 years ago

4 0

Answer:

300

Step-by-step explanation:

If all terms are negative then the result will come out positive.

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Hector's service club is raising money by wrapping presents in the mall. The function f\left(x\right)=3xf(x)=3x describes the am

mestny [16]

Given:

The function f(x) describes the amount of money, in dollars, the club will earn for wrapping x presents.

$f(x)=3x$

To find:

The f(658).

Solution:

We have,

$f(x)=3x$

Substitute x=658 to find the value of f(658).

$f(658)=3(658)$

$f(658)=1974$

It means, the club will earn $1974 for wrapping 658 presents.

Therefore, $f(658)=1974$ .

7 0

3 years ago

Let f(x) = 2x - 3. If f(x) = 15, what is x?

iragen [17]

Answer:

9=x

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Which is greater 8.2 or 8.23

faust18 [17]

I believe 8.23 is greater because 8.2 can be 8.20 so that’s why my answer is 8.23

8 0

4 years ago

Read 2 more answers

3. Janet is flying a kite on a string that is 75m long. The kite is 62m above the ground. Estimate the distance between Janet an

konstantin123 [22]

Answer: a) It will be a right triangle with a hypotenuse of 75 and a vertical leg that is 62.
b) The length of the kite string is 75 (given in the problem). However, I believe you are looking for the distance from the spot on the ground beneath the kite to Janet. That is about 42.2 m.

To find the missing distance in the right triangle. You have to use the Pythagorean Theorem. I set it up and solve it below.

a^2 + b^2 = c^2
x^2 + 62^2 = 75^2
x^2 + 3844 = 5625
x^2 = 1781
x = 42.2 (about)

3 0

3 years ago

PLZ HELP, AND PLZ EXPLAIN

shutvik [7]

Answer:

Step-by-step explanation:

To make it easy let's start by organizing our information :

AC=12 AND BD=8
ABCD is a rhombus
K and L are the midpoints of sides AD and CD
we notice that the rhombus ABCD is divided into four right triangles

What do you think of when you hear a right triangle ?

The pythagorian theorem !

AC and BD are khown so let's focus on them .

If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?

Simply because they are the diagonals of a rhombus .

ow let's apply the pythagorian theorem :

(AC/2)² + (BD/2)² = BC²
6²+4²=52
BC²= 52⇒ $\sqrt{52}$ =BC

Now we khow that : AB=BC=CD=AD= $\sqrt{52}$

This isn't enough . Let's try to figure out a way to calculate the length of KL wich is the base of the triangle

KL is parallel to AC
k is the midpoint of AD and L of DC

I smell something . yes! Thales theorem

KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE

KL/12= $\sqrt{52}$ /2* $\sqrt{52}$
KL/12=1/2⇒ KL=6

Now we have the length of the base kl

Now the big boss the height :

notice that you khow the length of KL
BD crosses kl from its midpoint and DL = $\sqrt{52}$ /2

What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D

DL²=(KL/2)²+D²
52/4= 9+ D²
D² = 52/4-9 +4 SO D=2

now the height of the trigle is H= BD-D= 8-2=6

NOw the area of the triangle is :

A=(KL*H)/2 ⇒ A= (6*6)/2=18

THE ANSWER IS 18 SQ.UN

5 0

3 years ago