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vivado [14]
3 years ago
11

Alaina has $28 in her account. She wants to purchase a pair of shoes that costs $45. If Alaina makes the purchase, which integer

will represent the amount of money in Alaina’s account?
Mathematics
1 answer:
adelina 88 [10]3 years ago
8 0

Answer:

$-17

Step-by-step explanation:

Well, she has $28, and wants to get a loan for a pair of shoes. That means she will have negative money in her account. This is because $45 is greater than $28 and the $28 is the one being taken from. This leaves the answer to be $-17.

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Which polynomial has factors of 4x-7 and x+4​
zzz [600]

Answer:

f(x)  = 4x² + 9x - 28

Step-by-step explanation:

Create the polynomial by multiplying (4x - 7) and (x + 4) together:

f(x) = 4x² + 16x - 7x - 28, or

f(x)  = 4x² + 9x - 28

Next time, please share the given answer choices.  Thanks.

4 0
3 years ago
A doctor prescribes 150 milligrams of a therapeutic drug that decays by about 15% each hour. To the nearest hour, what is the ha
Nikolay [14]

Answer:

4 hours

Step-by-step explanation:

The amount remaining at the end of each hour is 0.85 of the amount at the start of the hour. You want to find the exponent such that ...

... 0.85^x = 0.5 . . . . . x = the number of hours until half is left

... x·log(0.85) = log(0.5) . . . . . take the log to turn it to a linear equation

... x = log(0.5)/log(0.85) ≈ 4.265024

Rounded to the nearest  hour, x = 4.

3 0
3 years ago
For the straight line defined by the points (4,57) and (6,91) , determine the slope ( m ) and y-intercept ( ???? ). Do not round
Ksivusya [100]

\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{57})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{91}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{91}-\stackrel{y1}{57}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{4}}}\implies \cfrac{34}{2}\implies 17 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{57}=\stackrel{m}{17}(x-\stackrel{x_1}{4})\implies y-57=17x-68

\bf y=17x-11\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad \begin{cases} \stackrel{slope}{17}\\\\ \stackrel{y-intercept}{(0,-11)} \end{cases}

4 0
3 years ago
35 POINTS PLS HELP I HAVE UNTIL 12 TO FINISH
evablogger [386]

Answer: The first one is = 27.5

1/3 * 25 * 3.3 = 27.5

4 0
4 years ago
2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):
zlopas [31]
<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)

First pair of opposite sides:

<u>Slope:</u>

\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}

Second pair of opposite sides:

<u>Slope:</u>

\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\

So the diagonals measure the same, therefore this is a rectangle.

5 0
3 years ago
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