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goblinko [34]
3 years ago
15

Twice the square of an integer is 3 less than 7 times the integer. Find the integer!!

Mathematics
1 answer:
Solnce55 [7]3 years ago
3 0
The integer you’re looking for is 3
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Two companies modeled their profits for one year.
RoseWind [281]
We know the equation for company A is P(t) = 1.8(1.4)ᵗ.

and what we know about company B is that their equation is linear, and we also have 3 months in a table of values, and we can simply use two points from there to get the equation of company B, let's do so using (3,5) and (7, 25),

\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ 3 &,& 5~) 
%  (c,d)
&&(~ 7 &,& 25~)
\end{array}
\\\\\\
% slope  = m
slope =  m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{25-5}{7-3}\implies \cfrac{20}{4}\implies 5
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-5=5(x-3)
\\\\\\
y-5=5x-15\implies y=5x-10\implies p(t)=5t-10

now, the end of the year will be at the twelfth month, namely t = 12, and the four month well we know that t = 4.

how did each one fare?

\bf \stackrel{\textit{at the 4th month}}{\stackrel{\textit{company A}}{P(4)=6.91488}\qquad \qquad \stackrel{\textit{company B}}{p(4)=10}}
\\\\\\
\stackrel{\textit{at the end of the year}}{\stackrel{\textit{company A}}{P(12)\approx 102.04904}\qquad \qquad \stackrel{\textit{company B}}{p(12)=70}}

so, notice, on the fourth month B did better than A, but at the end of the year, A ended up better off than B.
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You can eliminate B. since a already beat it.

A.
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What is the missing value in the equation shown □ x1/10=0.034
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Step-by-step explanation:

Do the inverse operation so;

0.034 / 1/10 = 0.34

Now go back and subsitute,

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Answer:

A

Step-by-step explanation:

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