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Shtirlitz [24]
3 years ago
10

Ariana has a dimes and y nickels. She has at most 12 coins worth a minimum of

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
7 0

Answer:

Solution graph is attached in the answer area.

And one possible solution is (9, 2).

9 number of dimes and 2 number of nickels.

Step-by-step explanation:

Given that:

Number of dimes = a

Number of nickels = y

Total number of coins are at most 12 OR total number of coins are lesser than or equal to 12.

i.e. the inequality can be written as:

a+y \leq 12 ...... (1)

One dime is worth 10 cents or $0.10.

a number of dimes are worth $0.10a.

One nickel is worth 5 cents or $0.05.

y number of nickels are worth $0.05y.

Second inequality can be written as:

0.10a + 0.05 \ge 0.85

OR

2a+y\ge17 ...... (2)

a \ge 0, y \ge 0 ...... (3)

When we graphically represent the inequalities, the graph attached in the answer area represents the answer.

One solution is <em>(9, 2)</em>.

9 number of dimes and 2 number of nickels.

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Outside a home there is a keypad that will open the garage if the correct six-digit code is entered. How many codes are possible
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Answer:

1000000 = 1 MLN CODES

Step-by-step explanation:

According the terms of the problems the code has 6 digits or has 6 positions.

At 1st position any of 10 digits (0,1,2,3,4,5,6,7,8 or 9 ) can put

The digits can repeated, so at position 2 any of 10 difits can put.

At position 3 again any of 10 digits can put and similarly for each of next positions can be put any of 10 digits.

So each position of the code has 10 possible variants.

To find the total number of possible codes we have to multiply the number of variants for each position to each other.

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