Answer: The function is EVEN.
Step-by-step explanation:
For this exercise it is important to remember that:
1. A function f(x) is even if and only if:
for all "x"
2. A function f(x) is odd if and only if:
for all "x"
So knowing that, and given the following function k(x):

You can plug
in for "x", order to know if this is even. Then, you get:

Therefore, since:

You can determine that that the given function
is Even.
Answer:
Yes, with 12 feet leftover.
Step-by-step explanation:
For this problem, you will need to find the area of the floor and the area of both sides of the tent. To find the area of the floor, you will simply need to do 6(8) = 48. To find the area of the sides, you will need to use the Pythagorean theorem to find the height of the sides. Simply divide 6 by 2 to find b². So, the formula will be 3²+4² = c². Solve to get c = 5. Now, find the area of the rectangle by using the formula for area. 8(5) = 40. Multiply 40 by 2 because there are two sides. Now add the total area of both sides and the floor to get a total of 128. Now to see if the canvas can cover the area of the tent, do 140 - 128 to get 12. So the answer is yes, with 12 feet leftover.
Work:
Area of the floor:
6(8) = 48
Area of the sides:
A = 8(h)(2)
A = 16(h)
h² = 3² + 4²
h² = 9 + 16
= 
h = 5
A = 8(5)(2)
A = 80
Total area of the tent:
80 + 48 = 128
Total area of the canvas:
14(10) = 140
Answer to the question:
140 - 128 = 12
By the way, sorry for the late answer. I bet this was on a test, right?
So you need 3 cups of grapefruit juice to make 8 servings. you know that 32 divided by 8 is 4. so that means you need 4 times more grape fruit juice. that means you do 3 x 4 and get 12. so the answer is A.12 cups.
Answer:
-5
Step-by-step explanation:
For an expression to be undefined, the denominator must be equal to 0
Therefore, we must equate the denominator in the expression to 0
2v + 10 = 0
2v = 0 - 10
2v = -10
v = -10/2
v = -5
So in order for the expression to be undefined, v must be equal to -5
He finds 20 jeffys in bunny siuits and 1 bed to.sleep.