Question

Chemistry!! Please help

Answer 1

Answer:

5.3 × 10⁻¹⁷ mol·L⁻¹

Explanation:

Let s = the molar solubility.

                Cu₂S(s) ⇌ 2Cu⁺(aq) + S²⁻(aq); K_{sp} = 6.1 × 10⁻⁴⁹

E/mol·L⁻¹:                        2s             s

K_{sp}  =[Cu⁺]²[S²⁻] = (2s)²×s = 4s^3 = 6.1 × 10⁻⁴⁹

$s^{3}= \frac{6.1 \times 10^{-49}}{4} = 1.52 \times 10^{-49}$

$s = \sqrt[3]{1.52 \times 10^{-49}} \text{ mol/L} = 5.3 \times 10^{-17} \text{ mol/L}$