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Aneli [31]
2 years ago
12

HELP ME PLEASEEE ILL MARk u the brainliest

Chemistry
2 answers:
Novay_Z [31]2 years ago
8 0

Answer:

3rd or 4th answer is correct

belka [17]2 years ago
5 0

OPTION B is the correct answer

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Bicarbonate concentrate mixers may have a which are replaced on a routine basic.
Sidana [21]

Answer: True the bicarbonate mixture can help save time and few routine.

Explanation:

For the purpose of making dialysate for hemodialysis patient therapies a bicarbonate mixing and delivering systems designed to prepare a liquid sodium bicarbonate formulation comes in handy.

Certain systems like the SDS unit also allow for the transfer and distribution of acid concentrate solutions. We also provide stand-alone acid concentrate delivery systems using a variety of holding tanks and delivery methods. 

A challenge for hemodialysis providers is to properly provide bicarbonate solution in a cost effective manner. Preparation and disinfection can be time-consuming and labor intensive.

Bicarbonate however can corrode certain metals and painted surfaces leaving your preparation area encrusted and grimy.

Furthermore, if not mixed properly, bicarbonate can negatively affect the dialysate solution.

The answer to the above is true the bicarbonate mixture can help save time and few routine.

3 0
3 years ago
Fill in the blanks to correctly describe each separation process.
Dimas [21]

Answer:

C, B ,A(in the order of the blanks)

Explanation:

A centrifuge uses centrifugal force to seperate 2 substances with different densities, the lighter one at the top. This cannot be done with homogeneous mixtures

4 0
3 years ago
Neptunium-237 undergoes a series of α-particle and β-particle productions to end up as thallium-205. How many α particles and β
Fantom [35]
<h3>Answer:</h3>

8 alpha particles

4 beta particles

<h3>Explanation:</h3>

<u>We are given;</u>

  • Neptunium-237
  • Thallium-205
  • Neptunium-237 undergoes beta and alpha decay to form Thallium-205.

We are required to determine the number of beta and alpha particles produced to complete the decay series.

  • We need to know that when a radioisotope emits an alpha particle the mass number reduces by 4 while the atomic number decreases by 2.
  • When a beta particle is emitted the mass number of the radioisotope increases by 1 while the atomic number remains the same.

In this case;

Neptunium-237 has an atomic number 93, while,

Thallium-205 has an atomic number 81.

Therefore;

²³⁷₉₃Np → x⁴₂He + y⁰₋₁e + ²⁰⁵₈₁Ti

We can get x and y

237 = 4x + y(0) + 205

237-205 = 4x

4x = 32

 x = 8

On the other hand;

93 = 2x + (-y) + 81

but x = 8

93 = 16 -y + 81

y = 4

Therefore, the complete decay equation is;

²³⁷₉₃Np → 8⁴₂He + 4⁰₋₁e + ²⁰⁵₈₁Ti

Thus, Neptunium-237 emits 8 alpha particles and 4 beta particles to become Thallium-205.

5 0
2 years ago
What is the electron configuration of Zn2+
boyakko [2]
. 1s2 2s2 2p6 3s2 3p6 3d10 One point is earned for the correct configuration.
3 0
3 years ago
Which method can be used to find the range
lidiya [134]

Answer:

To find the range, first order the data from least to greatest. Then subtract the smallest value from the largest

3 0
2 years ago
Read 2 more answers
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