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Aneli [31]
2 years ago
12

HELP ME PLEASEEE ILL MARk u the brainliest

Chemistry
2 answers:
Novay_Z [31]2 years ago
8 0

Answer:

3rd or 4th answer is correct

belka [17]2 years ago
5 0

OPTION B is the correct answer

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ch3)2c(oh)ch2ch3 skeletal structure, Functional groups, compound type & alcohol class if it’s an alcohol
xxTIMURxx [149]

The skeletal structure of an organic compound is an abbreviated representation of its molecular structure, they are quick and easy to draw.

For example, the following image shows the skeletal structure of a compound:

The peaks represent the carbons. We must remember that carbon can have a maximum of 4 bonds.

Now, I will show you how is the structure of this specific compound:

This is ternary alcohol, called 2-methyl-2-butanol. If you see carefully, you will notice that each carbon has 4 bonds. The functional groups present will be OH. The skeletal structure will be:

6 0
1 year ago
Which stroke is this describing?
iren2701 [21]

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C. Compression

Explanation:

"...are compressed."

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3 years ago
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3 years ago
Valence Bond theory predicts that tin will use what hybrid orbitals in Snf5 -1​
LUCKY_DIMON [66]

Answer:

sp3d

Explanation:

The ground state electronic configuration of tin is written as; [Kr] 5s²4d¹⁰5p². Hybridization is a concept used to explain the combination of orbitals of appropriate energy to produce suitable orbitals that could be used for bonding.

In forming the compound Snf5^ -1, we have to hybridize the following orbitals on tin; 5p, 5d and 6s orbitals. This gives us a set of sp3d hybrid  hence the answer.

6 0
2 years ago
You are given a solution that is 518 mM lactose. You need to make up 4.5 L of 16.7 mM solution. What volume do you need to trans
OLga [1]

Answer:

The volume you need to transfer from the stock solution is 0.145 l

Explanation:

Since the number of moles of lactose in the volume of stock solution that you transfer will be the same as the number of moles of lactose in the final solution, you can use this expression:

number of moles in volume to transfer = number of moles in the final solution

Since number of moles = concentration * volume (if the concentration is expressed in molarity), then:

Ci * Vi = Cf * Vf

where:

Ci = concentration of the stock solution.

Vi = volume of the stock solution to be transferred.

Cf = concentration of the final solution

Vf = volume of the final solution

Then, replacing with the data:

518 mM * Vi = 16.7 mM * 4.5 l

Vi = 16.7 mM * 4.5 l / 518 mM

<u>Vi = 0.145 l or 145 ml</u>

Notice that any concentration unit can be used, as long as the units of the concentration of the stock and final solution are the same.

4 0
3 years ago
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