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wlad13 [49]
2 years ago
7

For the following chemical equation.

Chemistry
1 answer:
kotegsom [21]2 years ago
5 0

Sr is the limiting reactant.

Given the reaction equation;

2Sr + O2 (g) → 2SrO

2 moles of Sr reacts with 1 mole of O2

2 moles Sr will react with x mole of O2

x = 2 ×1/2

x = 1 mole of O2

Since we have more O2 than required, it is the reactant in excess, hence Sr is the limiting reactant.

Learn more: brainly.com/question/14225536

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maxonik [38]

Answer: The 234.74 grams of sample should be ordered.

Explanation:

Let the gram of  114 Ag to ordered be N_o

The amount required for the beginning of experiment = 0.0575 g

Time requires to ship the sample = 4.2hour = 252 min(1 hr = 60 min)

Half life of the sample ={t_{\frac{1}{2}} = 21 min

\lambda =\frac{0.693}{t_{\frac{1}{2}}}=\frac{0.693}{21 min}=0.033 min^{-1}

\log[N]=\log[N_o]-\frac{\lambda t}{2.303}

\log[0.0575 g]=\log[N_o]-\frac{0.033 min^{-1}\times 252 min}{2.303}

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The 234.74 grams of sample should be ordered.

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Explanation :

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