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wlad13 [49]
2 years ago
7

For the following chemical equation.

Chemistry
1 answer:
kotegsom [21]2 years ago
5 0

Sr is the limiting reactant.

Given the reaction equation;

2Sr + O2 (g) → 2SrO

2 moles of Sr reacts with 1 mole of O2

2 moles Sr will react with x mole of O2

x = 2 ×1/2

x = 1 mole of O2

Since we have more O2 than required, it is the reactant in excess, hence Sr is the limiting reactant.

Learn more: brainly.com/question/14225536

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Writing Chemical Equations
nignag [31]

Answer:    

The prefix di means 2 and the prefix hexa means 6.

As per IUPAC rules you must use the prefixes to indicate the number of atoms of each element in the formula.

So, the proper name for the compound C2H6 is dicarbon hexahydride.

Explanation:

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3 years ago
Can you please help me and can you show your work please
natali 33 [55]

Answer:

1. 25 moles water.

2. 41.2 grams of sodium hydroxide.

3. 0.25 grams of sugar.

4. 340.6 grams of ammonia.

5. 4.5x10²³ molecules of sulfur dioxide.

Explanation:

Hello!

In this case, since the mole-mass-particles relationships are studied by considering the Avogadro's number for the formula units and the molar mass for the mass of one mole of substance, we proceed as shown below:

1. Here, we use the Avogadro's number to obtain the moles in the given molecules of water:

1.5x10^{25}molecules*\frac{1mol}{6.022x10^{23}molecules} =25 molH_2O

2. Here, since the molar mass of NaOH is 40.00 g/mol, we obtain:

1.2mol*\frac{40.00g}{1mol} =41.2g

3. Here, since the molar mass of C6H12O6 is 180.15 g/mol:

45g*\frac{1mol}{180.15g}=0.25g

4. Here, since the molar mass of ammonia is 17.03 g/mol:

20mol*\frac{17.03g}{1mol}=340.6g

5. Here, since the molar mass of SO2 is 64.06 g/mol:

48g*\frac{1mol}{64.06g} *\frac{6.022x10^{23}molecules}{1mol} =4.5x10^{23}molecules

Best regards!

5 0
3 years ago
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