This answer will depend on if you are speaking about asexual reproduction or not.
Variety is possible here because the the product genes are half from the mother and half from the father. So a child might have blue eyes from his mother, but red hair from his father, etc. Different genetic mutations are the initial cause of all differentiation between genes, which are passed down from each generation to the next through this same process.
In Asexual reproduction, all reproductions are essentially clones of the parent, and no genetic variation, other than mutations will occur.
Answer:
<u>Question</u><u> </u><u>1</u><u> </u><u>:</u>
• A compound is ionic if it is made up of a metal or a cation (+) and a non metal or anion (-)
<u>Question</u><u> </u><u>2</u><u> </u><u>:</u>
• While naming ionic compounds, follow the formula → "metal" + "non-metal ending with <em>ide</em><em> </em>"
• i.e; Sodium Chloride:

<u>Question</u><u> </u><u>3</u><u> </u><u>:</u>
• The answer above that question is perfect.
<u>Question</u><u> </u><u>4</u><u> </u><u>:</u>
1 atom → Mono. But it is highly recommended to ignore it
2 atoms → DI
3 atoms → TRI
4 atoms → TETRA
5 atoms → PENTA ( such as pentaoxide )
7 atoms → HEPTA ( such as heptaoxide )
<u>Question</u><u> </u><u>5</u><u> </u><u>and</u><u> </u><u>6</u><u>:</u>
Are perfectly answered.
Ferric hydroxide decomposes to ferric oxide (iron(iii) oxide or rust) and water.
Answer:
The boiling point of HF is <u><em>higher than</em></u> the boiling point of H2, and it is <u><em>higher than</em></u> the boiling point of F2.
Explanation:
In HF, inter- molecule forces will be present between the hydrogen and fluorine atoms. There will be hydrogen bonding present among the hydrogen and fluorine atoms. Hydrogen bonds are strong bonds and hence the boiling point for HF would be high as much energy will be required to break these bonds.
H2 and F2 will only have intra-molecular attractions and there will be no hydrogen bonds present in them. As a result, their boiling point will be lower.
Answer:
Groups 14, 15, and 16 have 2,3, and 4 electrons in the p sublevel (p sublevel has 3 "spaces" AKA orbitals), because Hunds says one in each orbital before doubling up if you had 2 electrons, group 14, they would both be in the first orbital, with 3 electrons, group 15, two in the first orbital one in the 2nd none in the 3rd. With 4 electrons, group 16, then you would have 2 in the first 2 orbitals and NONE in the 3rd.
Explanation:
If you are in group 13 you only have 1 electron so it can only be in one orbital. with group 17, you have 5 electrons, so 2 in the first 2 in the second and 1 in the 3rd, correct for Hunds rule anyway. Noble gasses, group 18, have 6 elecctrons, so every orbital is full any way you look at it.