Answer:
The amount of oil was decreasing at 69300 barrels, yearly
Step-by-step explanation:
Given


Required
At what rate did oil decrease when 600000 barrels remain
To do this, we make use of the following notations
t = Time
A = Amount left in the well
So:

Where k represents the constant of proportionality

Multiply both sides by dt/A


Integrate both sides


Make A, the subject

i.e. At initial
So, we have:






Substitute
in 

To solve for k;

i.e.

So:

Divide both sides by 1000000

Take natural logarithm (ln) of both sides


Solve for k



Recall that:

Where
= Rate
So, when

The rate is:


<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>
Answer:
A
Step-by-step explanation:
I think it is a because if you mutiply and you will get your answer
Answer:
x > - 
Step-by-step explanation:
Given
6(x + 1) > 2x - 1 ← distribute parenthesis on left side
6x + 6 > 2x - 1 ( subtract 2x from both sides )
4x + 6 > - 1 ( subtract 6 from both sides )
4x > - 7 ( divide both sides by 4 )
x > - 
Answer:
sum of products expression = x₁x₂x₃' + x₁x₂'x₄ + x₁x₂x₄
Step-by-step explanation:
Given function ( f ) = x₁x₂'x₃' + x₁x₂x₄ + x₁x₂'x₃x₄'
using algebraic manipulation
f = x₁ [ x₂'x₃' + x₂x₄ + x₂'x₃x₄' ]
= x₁ [ x₂'( x₃' + x₃x₄') + x₂x₄ ]
next apply Boolean rules
a + bc = ( a + b )(a + c )
a' + a =1
hence
minimum sum-of-products expression = x₁x₂x₃' + x₁x₂'x₄ + x₁x₂x₄