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sweet [91]
3 years ago
11

The metal cover that seals the top of the cylinder

Physics
2 answers:
alex41 [277]3 years ago
8 0

Answer:

cylinder head

Explanation:

padilas [110]3 years ago
5 0

Answer:a lid

Explanation bob pulled the lid off the jar of pickles

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4 years ago
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A circular rod with a gage length of 3.5 mm and a diameter of 2.8 cmcm is subjected to an axial load of 68 kN . If the modulus o
Crank

To solve this problem, we will apply the concepts related to the linear deformation of a body given by the relationship between the load applied over a given length, acting by the corresponding area unit and the modulus of elasticity. The mathematical representation of this is given as:

\delta = \frac{PL}{AE}

Where,

P = Axial Load

l = Gage length

A = Cross-sectional Area

E = Modulus of Elasticity

Our values are given as,

l = 3.5m

D = 0.028m

P = 68*10^3 N

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A = \frac{\pi}{4}(0.028)^2 \rightarrow 0.0006157m^2

Replacing we have,

\delta = \frac{PL}{AE}

\delta = \frac{( 68*10^3)(3.5)}{(0.0006157)(200*10^9)}

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7 0
3 years ago
Scientists discover two planets orbiting a distant star. The average distance from the star to Planet A is 8 AU, and it takes 71
Mama L [17]

Answer: 11.2 AU

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Applying Kepler's 3rd law, we can find out the average distance of planet B to the star.

This Law states that for planets orbiting a same star, there exists a fixed relationship between the average distance to  the star, and the period of his orbit  around it, as follows:

K = T² / d³

So , in this case, we can write:

(da)³ / Ta² = (db)³ / (Tb)²

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When a 0.292 kg mass on a string is swung at 8.45 m/s, it feels a centripetal acceleration of 78.9 m/s^2. What is the radius of
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r=0.26m

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F=mv^2/r

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r=0.292*(8.45)^2/78.9

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A . ! Hope this helps
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