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pogonyaev
3 years ago
11

At the end of a race a runner decelerates from a velocity of 11.00 m/s at a rate of 0.300 m/s2. (a) how far does she travel in t

he next 16.0 s? m (b) what is her final velocity? m/s
Physics
1 answer:
inessss [21]3 years ago
8 0

given that initial velocity is

v_i = 11 m/s

deceleration is given as

a = -0.3 m/s^2

now we have to find the distance covered in 16 s

d = v_i * t + \frac{1}{2} at^2

d = 11*16 - \frac{1}{2}*0.3*16^2

d = 137.6 m

so it will cover 137.6 m distance

part b)

in order to find the final speed

v_f = v_i + at

v_f = 11 - 0.3*16

v_f = 6.2 m/s

so its speed will be 6.2 m/s

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