Question

At the end of a race a runner decelerates from a velocity of 11.00 m/s at a rate of 0.300 m/s2. (a) how far does she travel in the next 16.0 s? m (b) what is her final velocity? m/s

Answer 1

given that initial velocity is

$v_i = 11 m/s$

deceleration is given as

$a = -0.3 m/s^2$

now we have to find the distance covered in 16 s

$d = v_i * t + \frac{1}{2} at^2$

$d = 11*16 - \frac{1}{2}*0.3*16^2$

$d = 137.6 m$

so it will cover 137.6 m distance

part b)

in order to find the final speed

$v_f = v_i + at$

$v_f = 11 - 0.3*16$

$v_f = 6.2 m/s$

so its speed will be 6.2 m/s