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Mariulka [41]
2 years ago
6

calculate the eccentricity of jupiter's orbit if the aphelion is 816.62 million km and the perihelion is 741.52 million km

Physics
1 answer:
schepotkina [342]2 years ago
8 0
<h2>Answer:0.048</h2>

Explanation:

Let the length of perihelion be p

Let the length of aphelion be a

Let the length of semi major axis of the elliptical path be s

As we know that semi major axis is the average of perihelion and aphelion.

So,s=\frac{p+a}{2} =\frac{1558.14}{2}=779.07millionKm

Let the eccentricity of the elliptical path be e

e=1-\frac{p}{s}=1-\frac{741.52}{779.07}=0.048

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