Question

calculate the eccentricity of jupiter's orbit if the aphelion is 816.62 million km and the perihelion is 741.52 million km

Answer 1

Answer:0.048

Explanation:

Let the length of perihelion be $p$

Let the length of aphelion be $a$

Let the length of semi major axis of the elliptical path be $s$

As we know that semi major axis is the average of perihelion and aphelion.

So,$s=\frac{p+a}{2} =\frac{1558.14}{2}=779.07$$millionKm$

Let the eccentricity of the elliptical path be $e$

$e=1-\frac{p}{s}=1-\frac{741.52}{779.07}=0.048$