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zloy xaker [14]
3 years ago
6

A closely wound rectangular coil of 75.0 turns has dimensions of 22.0 cm by 45.0 cm . The plane of the coil is rotated from a po

sition where it makes an angle of 36.0 ° with a magnetic field of 1.00 T to a position perpendicular to the field. The rotation takes 6.00×10^−2 s .
Physics
1 answer:
pentagon [3]3 years ago
8 0

Answer:51.52 V

Explanation:

Given

N=75 turns

Area=22\times 45 cm^2

\theta =36^{\circ}

Emf induced =-N\frac{\mathrm{d}\phi }{\mathrm{d} t}

Emf=-75A\frac{B_2-B_1}{t}

Emf=-75\times 22\times 45\times 10^{-4}\frac{1(1-cos(90-36))}{6\times 10^{-2}}

Emf=51.52 V

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Alex777 [14]
X -> Y + 2Z

So there are 2 different particles. 1 mol of X produces 1 mol of Y and 2 moles of Z.

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Kps = s*(2s)^2 = s*4s^2=4s^3

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4 0
4 years ago
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Airida [17]

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Put the values where they belong and solve for Velocity.

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4 years ago
Consider three force vectors F~ 1 with magnitude 43 N and direction 38◦ , F~ 2 with magnitude 26 N and direction −140◦ , and F~
Rama09 [41]

Answer:

34.70 N

Explanation:

Given :

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F~y = 43 sin (38) + 26 sin (-140) + 27 sin (110)

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Ede4ka [16]

Answer:

A

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5 0
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Two particles are located on the x axis. particle 1 has a mass m and is at the origin. particle 2 has a mass 2m and is at x = +l
wlad13 [49]

The solution would be like this for this specific problem:

<span>
The force on m is:</span>

<span>
GMm / x^2 + Gm(2m) / L^2 = 2[Gm (2m) / L^2] -> 1

The force on 2m is:</span>

<span>
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x = L / (sqrt2 + 1) From here, we rationalize. 

x = L(sqrt2 - 1) / (sqrt2 + 1)(sqrt2 - 1) 

x = L(sqrt2 - 1) / (2 - 1) 


x = L(sqrt2 - 1) </span>

 

= 0.414L

 

<span>Therefore, the third particle should be located the 0.414L x axis so that the magnitude of the gravitational force on both particle 1 and particle 2 doubles.</span>

8 0
4 years ago
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