Point-slope form of a line: We need a point (x₀,y₀) and the slope "m";
y-y₀=m(x-x₀)
We have the next equation of line:
y=1/2 x-2 (slope-intercept form y=mx+b)
the slope of this line is 1/2 (m=1/2)
And any one point could be:
if x=0; then y=1/2 (0)-2=-2 (0,-2)
Therefore, we already have the point (0-,2) and the slope (m=1/2)
y-y₀=m(x-x₀)
y+2=1/2(x-0)
Answer: the point slope form of y=1/2 x-2; would be:
y+2=1/2(x-0)
Answer:
B
Step-by-step explanation:
Find the area of the circle with r = 36/2 Area1 = π r²
divide Area1 by two since the upper part of the figure is a semi-circle
then finally add and area of the rectangle Area2 = (18)(36)
Total area = Area 1 + Area 2
Given:
The graphed point is (60,-20).
To find:
The ordered pair that would form a proportional relationship with the given point.
Solution:
If y is proportional to x, then
Where, k is the constant of proportionality.
For the given point,
For option (A),
For option (B),
For option (C),
.
The point (-30,10) gives the same value of the constant of proportionality. So, the point (-30,10) forms a proportional relationship with the given point.
Therefore, the correct option is C.
Answer: I think u have to take away 12 from 36
