Question

How many solutions does this linear system have?

Answer 1

Answer:

one solution: (-1,1)

Step-by-step explanation:

we have

$y=x+2$ ----> equation A

$6x-4y=-10$ ----> equation B

Solve the system by substitution

Substitute equation A in equation B

$6x-4(x+2)=-10$

solve for x

$6x-4x-8=-10$

$6x-4x=-10+8$

$2x=-2$

$x=-1$

Find the value of y

$y=x+2$ ----> $y=-1+2=1$

The solution is the point (-1,1)

therefore

one solution: (-1,1)