There are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned from 14 volunteers.
Given that a school dance committee has 14 volunteers and each dance requires 3 volunteers at the door, 5 volunteers on the floor and 6 on floaters.
We are required to find the number of ways in which the volunteers can be assigned.
Combinations means finding the ways in which the things can be choosed to make a new thing or to do something else.
n
=n!/r!(n-r)!
Number of ways in which the volunteers can be assigned is equal to the following:
Since 2 have not been assigned so left over volunteers are 14-2=12 volunteers.
Number of ways =14
=14!/12!(14-12)!
=14!/12!*2!
=14*13/2*1
=91 ways
Hence there are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned.
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Answer:
3
Step-by-step explanation:
3 is the complete oposite of -1/3 in terms of slopes, therefore they are perpendicular to each other.
Answer:
12.75w + 25 = 114.25
w = 7
Step-by-step explanation:
since sarah is receiving 12.75 each week for a number of weeks, w (we don't know its value yet) we know that first part of the equation: that 12.75 is the coefficient next to w. Then we have the extra 25, so we know that adding 12.75w and 25 would give us sarah's total amount, which is 114.25.
to find out what w represents, we have to solve for it. solving for w means isolating it on one side. so, what we can do first is subtract 25 from both sides. that would then make the equation:
12.75w = 89.25
now, we have only one step left to isolating w, and that's to get 12.75 on the other side somehow. since we're multiplying 12.75 with w, and we're applying additive inverse properties, meaning the opposite of what is happening to cancel it out on the side it's in, we would divide 12.75 on both sides. in the left, 12.75 would cancel out, and in the right, we would divide 89.25 by 12.75. the quotient is 7.
now there's nothing left to take out to isolate w, so we have:
w = 7
sarah saved up for 7 weeks.
Answer:
The answer to your question is: 14 + 2√40 = 26.6 units
Step-by-step explanation:
Data
A ( -5, 4) B (-3, -2) C (4, -2) D (2, 4)
Formula
d = √(x2 - x1)² + (y2 - y1)²
Perimeter = dAB + dBC + dCD + dAD
Process
dAB = √(-3 + 5)² + (-2 - 4)²
dAB = √(2)² + (-6)²
dAB = √4 + 36
dAB = √40 units
dBC = √(4 + 3)² + (-2 + 2)²
dBC = √(7)²
dBC = √49
dBC = 7 units
dCD = √(2 - 4)² + (4 + 2)²
dCD = √(2)² + (6)²
dCD = √40 units
dAD = √(2 + 5)² + (4 - 4)²
dAD = √49
dAD = 7 units
Perimeter = √40 + 7 + √40 + 7
Perimeter = 14 + 2√40 = 26.6 units
Answer:
4512.
Step-by-step explanation:
We are asked to find the number of five-card hands (drawn from a standard deck) that contain exactly three fives.
The number of ways, in which 3 fives can be picked out of 4 available fives would be 4C3. The number of ways in which 2 non-five cards can be picked out of the 48 available non-five cards would be 48C2.
We can choose exactly three fives from five-card hands in 
ways.
Therefore, 4512 five card hands contain exactly three fives.
