Answer:
Advance tickets=$25
Same-day tickets=$15
Step-by-step explanation:
Complete question below:
Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $ 40. For one performance, 25 advance tickets and 30 same-day tickets were sold. The total amount paid for the tickets was $1075 . What was the price of each kind of ticket?
Let
advance tickets=x
Same-day tickets=y
Combined cost of advance and same-day tickets=$40
It means,
x+y=40 Equ (1)
25 advance tickets and 30 same-day tickets=$1075
It means,
25x+30y=1075 Equ(2)
From (1)
x+y=40
x=40-y
Substitute x=40-y into (2)
25x+30y=1075
25(40-y)+30y=1075
1000-25y+30y=1075
5y=1075-1000
5y=75
Divide both sides by 5
5y/5=75/5
y=15
Recall,
x+y=40
x+15=40
x=40-15
=25
x=25
Advance tickets=$25
Same-day tickets=$15
Check
25x+30y=1075
25(25)+30(15)=1075
625+450=1075
1075=1075
she should use 2 by 6
Step-by-step explanation:
2 divided by 6 will give 0.3 in 1d.p
Answer:
165m
Question:
Artur, Olga and Wiktor participated in the race. They started from the same place at the same time and run at constant speeds. When Artur finished the race, Olga was 15 m to the finish,
and Wiktor was 35 m. When Olga finished the race, Wiktor remained 22 m to the finish. At what distance was the race held?
Step-by-step explanation:
Let Artur distance covered be =>x
When Artur covered distance x:
Olga was 15m from x
Olga = x - 15
Wiktor was 35m from x
Wiktor = x - 35
When Olga covered distance x:
Wiktor was 22m from x
The ratio of Olga to Wiktor:
(x-15)/(x-35) = x/(x-22)
Cross multiply
(x-15)(x-22) = x(x-35)
x² - 15x - 22x + 330 = x² - 35x
x² -37x +330 - x² + 35x = 0
-2x = -330
x = (-330)/(-2)
x = 165m
The race held at 165m distance
Answer:
false
Step-by-step explanation: