Find the dimensions of a rectangle whose area is 306cm2 and whose perimeter is 70 cm
1 answer:
You might be interested in
Answer:
18.28 m
Step-by-step explanation:
Given the flower garden in the question :
The shape is composite and can be divided into 2 semicirles and rectangle
The perimeter of a semicircle is the Circumference of the semicircle = πr
Hence, 2 semicirles = 2πr
Radius of semicircle = 2/2 = 1
Perimeter = 2 * 3.14 * 1² = 2 * 3.14 * 1 = 6.28 m
The perimeter of rectangle; length and width are 6m and 2 m respectively :
Perimeter of rectangle = 2(l + w) = 2(4+2) = 2(6) = 12m
Tve perimeter of garden = 6.28 + 12 = 18.28 m
Answer:
P(Z < 2.37) = 0.9911.
Step-by-step explanation:
We are given that Let z denote a random variable that has a standard normal distribution.
Let Z = a random variable
So, Z ~ Standard Normal(0, 1)
As we know that the standard normal distribution has a mean of 0 and variance equal to 1.
Z = ~ N(0,1)
where, = mean = 0
= standard deviation = 1
Now, the probability that z has a value less than 2.37 is given by = P(Z < 2.37)
P(Z < 2.37) = P(Z < ) = P(Z < 2.37) = 0.9911
The above probability is calculated by looking at the value of x = 2.37 in the z table which has an area of 0.9911.