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Galina-37 [17]
4 years ago
7

Olivia is growing roses and keeps track of how much fertilizer (in ounces) she adds to the soil and how many blooms each rose bu

sh has. She finds a linear relationship that can be modeled by the equation y = 1.345x + 4. When will Olivia only have 4 blooms?
A) When she adds no fertilizer.
B) Every bush will only have 4 blooms.
C) When she only adds 1 ounce of fertilizer.
D) It is not possible for her to only have 4 blooms.
Mathematics
2 answers:
dusya [7]4 years ago
8 0

Answer:

<em>She needs to add no fertilizer, option A)</em>

Step-by-step explanation:

<u>Equation of a Line:</u>

According to the conditions of the question, being x the ounces of fertilizer Olivia adds to the soil, and y the number of blooms each rose bush has, the relation between them is

y = 1.345x + 4

It's bee required to compute the value of x such that the roses have 4 blooms, thus

1.345x + 4=4

Solving for x

1.345x=4-4=0

x=0

This means she needs to add no fertilizer, option A)

diamong [38]4 years ago
8 0

Answer:

A)    When she adds no fertilizer.

Step-by-step explanation:

Since 4 is the y-intercept the x-value must be 0. This only happens when she adds no fertilizer..

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IgorLugansk [536]

Answer:

b) Then z(s) is in the rejection region for H₀. We reject H₀. The p-value is smaller than α/2

c)CI 95 %  =  ( 0.00002 ;  0.09998)

Step-by-step explanation: In both cases, the size of the samples are big enough to make use of the approximation of normality of the difference of the proportions.

Recent Sample

Sample size    n₁  =  1000

Number of events of people with financial fitness more than fair

x₁  =  410

p₁ =  410/ 1000  =  0.4     then q₁ = 1 - p₁    q₁ =  1 -  0.4    q₁  = 0.6

Sample a year ago

Sample size    n₂ =  1200

Number of events of people with financial fitness more than fair

x₂  =  420

p₂  =  420/1200     p₂ = 0.35   q₂  =  1 - p₂    q₂  = 1 - 0.35   q₂ = 0.65

Test Hypothesis

Null Hypothesis                                  H₀              p₁  =  p₂

Alternative Hypothesis                      Hₐ              p₁  ≠  p₂

CI  95 % then significance level  α  =  5%   α  = 0.05    α/2  = 0.025

To calculate p-value:

SE  =  √ (p₁*q₁)/n₁  +  (p₂*q₂)/n₂

SE  =  √ 0.4*0.6/1000 +  0.65*0.35/1200

SE  =  √ 0.00024 + 0.000189

SE = 0.021

z(s) =  ( p₁ - p₂ ) / SE

z(s) = ( 0.4 - 0.35 )/0.021

z(s) = 0.05/ 0.021

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Comparing

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Then z(s) is in the rejection region for H₀. We reject H₀

CI 95 %  =  ( p₁  -  p₂ )  ±  2.38*SE

CI 95 %  =  ( 0.05 ± 2.38*0.021 )

CI 95 %  =  ( 0.05 ± 0.04998)

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Answer:

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Step-by-step explanation:

To solve x-7 = \sqrt{-4x+28}, use inverse operations by squaring both sides of the equal sign.

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Now check each solution into the original equation to be sure it solve the solution and is not extraneous.

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and

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Step-by-step explanation:

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