Represent these consecutive numbers (assuming that they are all integers):
x
x+1
x+2
x+3
x+4
x+5
and so on
x+8
x+9 is the tenth number. x+9 = 10, so x = 9.
Think of it this way: there are 10 consecutive numbers, and the last one is 10.
Working backwards, we get the sequence 10, 9, ... 3, 2, 1.
The sum of such an arith sequence is equal to the count of the numbers times the average of the first and last terms:
sum here = 10(1+10)/2 = 5(11) = 55 (answer)
Answer:
Step-by-step explanation:
21 is c
Answer:
y=mx+b
Step-by-step explanation:
Answer:
(2 + 1)^2 + 2 = 10 - 6
Falso
Step-by-step explanation:
109 / 5000
El lado izquierdo
11
no es igual al lado derecho
4
, lo que significa que la declaración dada es falsa.
Falso
