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Oxana [17]
3 years ago
6

Answers for the 2 boxes please :)​

Mathematics
2 answers:
jek_recluse [69]3 years ago
7 0

Answer:

(0, 3 )

Step-by-step explanation:

Given the 2 equations

x + 3y = 9 → (1)

- 2x + 2y = 6 → (2)

Multiplying (1) by 2 and adding to (2) will eliminate the x- term

2x + 6y = 18 → (3)

Add (2) and (3) term by term to eliminate x, that is

0 + 8y = 24

8y = 24 ( divide both sides by 8 )

y = 3

Substitute y = 3 into either of the 2 equations and solve for x

Substituting into (1)

x + 3(3) = 9

x + 9 = 9 ( subtract 9 from both sides )

x = 0

solution is (0, 3 )

Roman55 [17]3 years ago
5 0
X= 0 y= 3
You have to make either the xs or ys the same so you could find out the other value first

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3 years ago
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Which quadratic equation is equivalent to (x2 – 1)2 – 11(x2 – 1) 24 = 0? u2 – 11u 24 = 0 where u = (x2 – 1) (u2)2 – 11(u2) 24 wh
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The equivalent equation of the quadratic equation (x² – 1)² – 11(x² – 1) + 24 = 0 is u² - 11² + 24 = 0

<h3>How to determine the equivalent equation?</h3>

The equation is given as:

(x² – 1)² – 11(x² – 1) + 24 = 0

Let u = x² - 1

So, we have:

u² - 11² + 24 = 0

Hence, the equivalent equation of the quadratic equation (x² – 1)² – 11(x² – 1) + 24 = 0 is u² - 11² + 24 = 0

Read more about quadratic equation at:

brainly.com/question/8649555

#SPJ4

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3 years ago
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