Answer:
B. survey a random sample of 7th-grade students
Step-by-step explanation:
this answer would make the most sense because it is a example of a random statistical question.
Answer:
x1 = 1.54
x2 = -4.54
Step-by-step explanation:
just use calculator
Answer: (0,1)
Step-by-step explanation:
If 
and 
are two point son a coordinate plane and (x,y) dividing it in a ratio of m: n.
Then , the coordinates of (x,y) is given by :-
Given : On a coordinate plane, a line is drawn from point A to point B. Point A is at (2, - 3) and point B is at (- 4, 9).
Then , the x- and y- coordinates of point E, which partitions the directed line segment from A to B into a ratio of 1:2 :
Hence, the x- and y- coordinates of point E = (0,1)
Answer:
x^2 + 4x * (3 - sqrt(x)) - 2(5 + sqrt(x))
Step-by-step explanation:
Firstly let us split this up, we need to first work out what g(h(x)) is:
h(x) = Sqrt(x) so g(h(x)) = g(sqrt(x)) = sqrt(x) - 2
Now to work out f(g(h(x))) = f(sqrt(x) - 2) = (sqrt(x) - 2)^4 + 6
= (sqrt(x) - 2) * (sqrt(x) - 2) * (sqrt(x) - 2) * (sqrt(x) - 2) - 6
= (x - 2 * sqrt(x) + 4) * (x - 2 * sqrt(x) + 4) - 6
= x^2 - 2x * sqrt(x) + 4x - 2x * sqrt(x) + 4x - 8 * sqrt(x) + 4x - 8 * sqrt(x) + 16 - 6
= x^2 - 4x * sqrt(x) + 12x - 16 * sqrt(x) + 10
= x^2 + 4x * (3 - sqrt(x)) - 2(5 + sqrt(x))
From Newton’s Second Law of Motion, the force needed to accelerate a moving object of mass m at acceleration a is given by ;
F = ma
In this case, m = 5kg, a = 6m/s^2 and we want to find F
F = 5 x 6
F = 30N
Therefore, a force of 30N is needed to accelerate a 5kg object at 6m/s^2.
