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Aleksandr-060686 [28]
3 years ago
12

Two trains are traveling at a constant rate which train has the greater speed

Mathematics
1 answer:
notka56 [123]3 years ago
3 0
Neither cause there both at the same constant rate so one train wouldn’t be traveling at a greater speed unless there is something missing from the question being asked like the actual speed of each individual train then there would be one train traveling at a greater speed
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Find a positive angle less than one revolution around the unit circle that is co-terminal with the given angle: 52pi/5
Ludmilka [50]
We know that
Two angles are said to be co-terminal <span>if they have the same initial side and </span>
<span>the same terminal side. 
</span>
(52π/5)-----> 10.4π<span>
so
</span>(52π/5)-5*2π------> (2π/5)

the answer is
the positive angle less than one revolution around the unit circle that is co-terminal with angle of 52π/5 is 2π/5

7 0
3 years ago
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Can u help me answer dis
gavmur [86]

Answer:

the base is 10 and the height is 6.4

3 0
2 years ago
Explain how to solve the equation and then check the solution.<br><br> 9 = q – 4
Vika [28.1K]

Assignment: \bold{Solve \ And \ Check \ Equation: \ 9=q-4}

<><><><><><><>

Answer: \boxed{\bold{q=13}}

<><><><><><><>

Explanation: \downarrow\downarrow\downarrow

<><><><><><><>

[ Step One ] Switch Sides

\bold{q-4=9}

[ Step Two ] Add 4 To Both Sides

\bold{q-4+4=9+4}

[ Step Three ] Simplify

\bold{q=13}

[ Step Four ] Check Your Work

\bold{13 \ - \ 4 \ = \ 9}

[ Step Five ] Question: Is Equation Correct

\bold{Equation \ Is \ Correct, \ Therefore \ q=13}

<><><><><><><>

\bold{\rightarrow Mordancy \leftarrow}

5 0
3 years ago
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The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.
Mama L [17]

Answer:

a) P(Y > 76) = 0.0122

b) i) P(both of them will be more than 76 inches tall) = 0.00015

   ii) P(Y > 76) = 0.0007

Step-by-step explanation:

Given - The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.

To find - (a) If a man is chosen at random from the population, find

                    the probability that he will be more than 76 inches tall.

              (b) If two men are chosen at random from the population, find

                    the probability that

                    (i) both of them will be more than 76 inches tall;

                    (ii) their mean height will be more than 76 inches.

Proof -

a)

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{S.D}) > \frac{( 76- mean)}{S.D})

                 = P(Z >  \frac{( 76- mean)}{S.D})

                 = P(Z > \frac{76 - 69.7}{2.8})

                 = P(Z > 2.25)

                 = 1 - P(Z  ≤ 2.25)

                 = 0.0122

⇒P(Y > 76) = 0.0122

b)

(i)

P(both of them will be more than 76 inches tall) = (0.0122)²

                                                                           = 0.00015

⇒P(both of them will be more than 76 inches tall) = 0.00015

(ii)

Given that,

Mean = 69.7,

\frac{S.D}{\sqrt{N} } = 1.979899,

Now,

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{\frac{S.D}{\sqrt{N} } })) > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- 69.7)}{1.979899 }))

                 = P(Z > 3.182)

                 = 1 - P(Z ≤ 3.182)

                 = 0.0007

⇒P(Y > 76) = 0.0007

6 0
3 years ago
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svet-max [94.6K]

Answer:

-4( 4x^2 -y^2)

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so I did the step on the paper

first line : is the equation itself

2nd line : I multiple the term in the parentheses together

3rd line: I multiple the - 2 to the term I got

4th line : I simplify it

6 0
3 years ago
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