All categories

2 years ago

Write the decimal 0.532 as a percent. a. 53.2% b. 532% C. 5.32% d. 0.532%

Mathematics

2 answers:

stepan [7]2 years ago

6 0

I believe it would be a.53.2%

vichka [17]2 years ago

4 0

The answer would be 53.2% because 1.0 is 100%

You might be interested in

PLEASE HELP!!!

zloy xaker [14]

Answer:

Step-by-step explanation:

8 0

2 years ago

use Taylor's Theorem with integral remainder and the mean-value theorem for integrals to deduce Taylor's Theorem with lagrange r

Vadim26 [7]

Answer:

As consequence of the Taylor theorem with integral remainder we have that

$f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \int^a_x f^{(n+1)}(t)\frac{(x-t)^n}{n!}dt$

If we ask that $f$ has continuous $(n+1)$ th derivative we can apply the mean value theorem for integrals. Then, there exists $c$ between $a$ and $x$ such that

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}dt = \frac{f^{(n+1)}(c)}{n!} \int^a_x (x-t)^n d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{n+1}}{n+1}\Big|_a^x$

Hence,

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{(n+1)}}{n+1} = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1} .$

Thus,

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}$

and the Taylor theorem with Lagrange remainder is

$f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}$ .

Step-by-step explanation:

5 0

3 years ago

Solve |x - 1|>4 a. {x|x< -5 or x> 5} b. {x|-3< x< 5} c. {x|x< -3 or x> 5}

Karo-lina-s [1.5K]

|x - 1| > 4 ⇔ x - 1 > 4 or x - 1 < -4 |add 1 to both sides

x > 5 or x < -3

Answer: c. {x| x < -3 or x > 5}.

5 0

3 years ago

Will mark brainlest, this is trig.

MrRa [10]

Answer:

Step-by-step explanation:

i have no idea but i thinkit is A.or D i think the kid is right with a different answer

happy to help

8 0

3 years ago

What is the volume of the cylinder

kogti [31]

Answer:

Step-by-step explanation:

Volume of the figure = Volume of cylinder + Volume of cone

Note: A cone having the same radius and height as cylinder have a volume (1/3) of cylinder

Volume of cone=(1/3)*96=32

Volume of the figure = 32+96=128

5 0

2 years ago