In order to solve this problem, you have to find the lowest common denominator. Take multiples of both 6 and 4 and see which is the lowest you have in common.

4: 4, 8, 12, 16, 20

6: 6, 12, 18, 24

So 12 is the lowest common multiple....

5/6 x ?/? = ?/12 (you have to multiply the numerator and the denominator by the same number)

3/4 x ?/? = ?/12 (you have to multiply the numerator and the denominator by the same number)

When the denominators are the same, you can subtract the numerators. The denominator will stay 12!

Step-by-step explanation:

YAY! I want a brain

8 0

3 years ago

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The rectangle below has an area of 6n^4+20n^3+14n^26n 4 +20n 3 +14n 2 6, n, start superscript, 4, end superscript, plus, 20, n,

Sindrei [870]

Given:

Area of rectangle = $6n^4+20n^3+14n^2$

Width of the rectangle is equal to the greatest common monomial factor of $6n^4, 20n^3,14n^2$ .

To find:

Length and width of the rectangle.

Solution:

Width of the rectangle is equal to the greatest common monomial factor of $6n^4, 20n^3,14n^2$ is

$6n^4=2\times 3\times n\times n\times n\times n$

$20n^3=2\times 2\times 5\times n\times n\times n$

$14n^2=2\times 7\times n\times n$

Now,

$GCF(6n^4, 20n^3,14n^2)=2\times n\times n=2n^2$

So, width of the rectangle is $2n^2$ .

Area of rectangle is

$Area=6n^4+20n^3+14n^2$

Taking out GCF, we get

$Area=2n^2(3n^2+10n+7)$

We know that, area of a rectangle is the product of its length and width.

Since, width of the rectangle is $2n^2$ , therefore length of the rectangle is $(3n^2+10n+7)$ .

5 0

3 years ago

Can you help me with this

marishachu [46]

Answer:

Step-by-step explanation:

8 0

3 years ago

WILL GIVE BRAINLIST PLS HELP Find z. Just write the number. Answer should be a whole number.

kakasveta [241]

Answer:

Step by Step Explanation

8 0

3 years ago

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