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AnnyKZ [126]
3 years ago
11

In a certain city , the hourly wage of workers on temporary employment crontracts is normally distributed. The mean is $15 and t

he standar deviation is $3. What percentage of temporary workers earn less than $12 per hour?
A) 6%
B) 16%
C) 26%
D) 36%
Mathematics
1 answer:
Doss [256]3 years ago
4 0

Answer:

16%

Step-by-step explanation:

The mean is $15 and the standar deviation is $3.

mean = 15  and SD = 3

We need to find percentage less than 12 per hour

P(x<12)= P(x=12)

to find P(x=12) we find z-score

z= \frac{x-mean}{SD} =\frac{12-15}{3} =-1

Now use z-score table . z-score = 0.1587

P(x=12)=0.1587

To get percentage we multiply by 100

0.1587 * 100 = 15.87 = 16%

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maw [93]
<span>Rock, Carbon, Water, Nitrogen</span>
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3 years ago
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The ratio of the geometric mean and arithmetic mean of two numbers is 3:5, find the ratio of the smaller number to the larger nu
IgorC [24]

Answer:

\frac{1}{9}

Step-by-step explanation:

Let the numbers be x,y, where x>y

The geometric mean is

\sqrt{xy}

The Arithmetic mean is

\frac{x + y}{2}

The ratio of the geometric mean and arithmetic mean of two numbers is 3:5.

\frac{ \sqrt{xy} }{ \frac{x + y}{2} }  =  \frac{3}{5}

We can write the equation;

\sqrt{xy}  = 3

or

xy = 9 -  -  - (2)

l

and

\frac{x + y}{2}  = 5

or

x + y = 10 -  -  - (2)

Make y the subject in equation 2

y = 10 - x -  -  - (3)

Put equation 3 in 1

x(10 - x) = 9

10x -  {x}^{2}  = 9

{x}^{2}  - 10x + 9 = 0

(x - 9)(x - 1) = 0

x =1  \: or \: 9

When x=1, y=10-1=9

When x=9, y=10-9=1

Therefore x=9, and y=1

The ratio of the smaller number to the larger number is

\frac{1}{9}

3 0
3 years ago
Phyllis invested 50000 dollars, a portion earning a simple interest rate of 5 percent per year and the rest earning a rate of 7
Elodia [21]

Answer:

The amount invested at 5% was $39,000 and the amount invested at 7% was $11,000

Step-by-step explanation:

we know that

The simple interest formula is equal to

I=P(rt)

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

Let

x-----> the amount invested at 5%

50,000-x -----> the amount invested at 7%

so

t=1\ year\\ I=\$2,720\\r_1=0.05\\r_2=0.07\\P_1=\$x\\P_2=\$(50,000-x)

substitute in the formula above

2,720=x(0.05*1)+(50,000-x)(0.07*1)

solve for x

2,720=0.05x+3,500-0.07x

0.07x-0.05x=3,500-2,720\\0.02x=780\\x=\$39,000

(50,000-x)=\$11,000

therefore

The amount invested at 5% was $39,000 and the amount invested at 7% was $11,000

5 0
3 years ago
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Rus_ich [418]
For number 9 put the equation in the graphing calculator and see what the outcome is
5 0
3 years ago
Need help ASAP
madreJ [45]

Answer:

A 1/4

Step-by-step explanation:

2/3 x = 1/6

2x/3 = 1/6

2x/3 = 1/2x3

The answer  is 1/4

8 0
3 years ago
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