1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gnoma [55]
3 years ago
9

A triangle has side lengths of 4 inches, 5 inches, y + 1 inches. Another triangle has side lengths of 2 inches, x inches, 3 inch

es.
These two figures are the image and pre–image of a dilation.
Mathematics
2 answers:
garik1379 [7]3 years ago
7 0

Answer:

X= 2.5

Y= 5

Step-by-step explanation:

son4ous [18]3 years ago
3 0

Answer:

x = 2.5.

y = 5.

Step-by-step explanation:

As they are image and pre-image of a dilation they are similar triangles, so the corresponding sides are in the same ratio.

4/2 = 5/x

2 = 5/x

2x = 5

x = 2.5.

Also:

4/2 = (y + 1)/ 3

2 = (y + 1) / 3

y + 1 = 6

y = 5.

You might be interested in
I AM GIVING BRAINLIEST
spayn [35]

Answer:

The first choice is correct

Step-by-step explanation:

$32.00 x 15% = 4.80. 32.00-4.80=27.20. Another way to work it is the first choice, subtracting 15% from 100% and then multiplying 85% by $32.00. Same answer

7 0
3 years ago
If, P(x,y) is a point on the unit circle determined by real number δ, then tanδ = what
Lisa [10]
\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
=\cfrac{y}{r}
=\cfrac{1}{csc(\theta)}
\\ \quad \\\\
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}
=\cfrac{x}{r}
=\cfrac{1}{sec(\theta)}
\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
=\cfrac{y}{x}
=\cfrac{sin(\theta)}{cos(\theta)}

\bf cot(\theta)=\cfrac{adjacent}{opposite}
=\cfrac{x}{y}
=\cfrac{cos(\theta)}{sin(\theta)}
\\ \quad \\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
=\cfrac{r}{y}
=\cfrac{1}{sin(\theta)}
\\ \quad \\\\
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}
=\cfrac{r}{x}
=\cfrac{1}{cos(\theta)}\\\\
-------------------------------\\\\
P(x,y)\implies \delta\qquad tan(\delta)=\cfrac{y}{x}
5 0
3 years ago
Convert 13 weeks to seconds.
dimaraw [331]

The value of 13 weeks in seconds is 7862400 seconds

<h3>Conversion of weeks to seconds</h3>

In order to convert weeks to seconds, we will use the following conversion factor

1week = 7 days

13weeks = 91days

<u>Convert days to hours</u>

Since 24 hours = 1 day, then;

91 days = (91*24)

91 days = 2184 hours

Convert hours to seconds

1 hour = 3600secs

Hence 2184 hours = (2184*3600)

2184 hours = 78624000 seconds

Hence the value of 13 weeks in seconds is 7862400 seconds

Learn more on conversion on weeks to seconds here: brainly.com/question/11947673

#SPJ1

8 0
1 year ago
Is a triangle with the side lengths 28,20,19 a right triangle
vova2212 [387]

Answer:

No

Step-by-step explanation:

plug the numbers into Pythagorean theorem

c^2 =a ^2 + b^2

28^2 = 20^2 + 19^2

784 = 400+361

784 = 761

No its not

4 0
3 years ago
Read 2 more answers
Evaluate the expression P (9,1)=_____
kvasek [131]
P(9,1)=\dfrac{9!}{8!}=9
3 0
3 years ago
Read 2 more answers
Other questions:
  • Find the distance between the points (0, 2) and (4, 5).
    13·1 answer
  • A triangle has side lengths of 7 in., 9 in., and 11 in. Determine whether this is a right triangle and why.
    15·1 answer
  • paul a dentist determined that the number of cavities that develops in his patients mouth each year varies inversely to the numb
    10·2 answers
  • Help me please, thank you.
    10·1 answer
  • Evaluate the expression: 5 + (1 + 1)3 × 2.
    11·2 answers
  • Quanto é o resultado e como ae resolve a seguinte operação: 1.205 × 32 Me ajudem preciso para hj.
    12·1 answer
  • WILL GIVE BRAINLIEST!!!!
    11·1 answer
  • A dietitian is interested in the average amount of time teenagers exercise per week. Based on previous studies, teenagers exerci
    13·1 answer
  • Which point represents 3.9?
    9·2 answers
  • Simplify and evaluate without a calculator. 3*(m-4)-n*(m-4) if m=5 and n=3
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!