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Galina-37 [17]
2 years ago
8

There are 3 people at a party. If each person must shake hands with every other person at the party exactly once, how many hands

hakes will there be?
Mathematics
1 answer:
Dima020 [189]2 years ago
5 0
<h2>Answer:</h2>

The total number of handshakes that would happen between the three people are:

                                    3

<h2>Step-by-step explanation:</h2>

There are three people at a party.

Let they be denoted by A,B and C.

Now, the total number of handshakes that would occur will be denoted by:

      AB, AC and BC

where AB denotes that A and B shake hands.

AC denote that A and C shake hands.

and BC denote that B and C shake hands.

Hence, total number of handshakes are:

                           3

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The producer of the news station posted an article about the high school's football championship ceremony on anew website. The w
sasho [114]

Incomplete question. The full question read;

The producer of the news station posted an article about the high school’s football championship ceremony on a new website. The website had 500 views after four hours. Create a table to show how many views the website would have had after the first, second, and third hours after posting if the website receives views at the same rate. How many views would the website receive after 5 hours?

Answer:

<u>625 views</u>

Step-by-step explanation:

<em>Remember,</em> we are told to <u>base our calculation on the assumption that the website receives views at the same rate.</u>

Hence, if after 4 hours there were 500 views, it means the average views per hour would be 500/4 = 125 views. So for every hour, there would be 125 added views to the total.

In other words,

First hour: <u>125 views</u>

Second hour:<u> </u><u>250 views (125 views + 125 views</u>)

Third hour: <u>375 views (250 views + 125 views)</u>

Fourth hour: <u>500 views (375 views + 125 views)</u>

Fifth hour:<u> 625 views (500 views + 125 views)</u>

7 0
2 years ago
Two of the 240 passengers are chosen at random. Find the probability that
hjlf

Step-by-step explanation:

there are in total 240 passengers.

out of these 240, there are 150+30=180 passengers that are in holiday.

and 240-180 = 60 passengers are not.

if we pick one passenger then the probability is 180/240 = 3/4 = 0.75 that he/she is on holiday.

remember : desired "events" over total "events".

i)

now we pick 2 passengers.

the probabilty for the first one to be on holiday is again

3/4 or 0.75.

if that event happens, then we have only 179 passengers out of now 239 to be on holiday.

and to pick one out of that pool to be on holiday is then

179/239 = 0.748953975...

and for both events to happen in one scenario we need to multiply both probabilities (it is an "and" relation, while an addition would be for an "exclusive or" relation).

the probabilty that we pick 2 passengers on holiday is

3/4 × 179/239 = 0.561715481... ≈ 0.5617

we cannot simply square the basic probability of 0.75 (0.75² = 0.5625), because that would mean we pick one passenger, then put him back into the crowd, and then pick a second time (with a chance to pick the same person again). like with rolling a die.

but that is not the scenario as I understand it. it is to pick a passenger, then keep that person singled out and pick a second passenger. hence the difference.

ii)

exactly one of the two is in holiday.

that means

either the first one is on holiday and the second one is not, or the the second one is and the first one is not.

now we model this logic statement in probabilty arithmetic.

please note that after the first pull we need to update the numbers for the remaining pool depending on the result of the first pull.

the total remaining is in both cases 239. but either the remaining people on holiday go down to 179 (and not in holiday stays 60), or the remaining people not on holiday go down to 59 (and on holiday stays 180).

so, the first one is on holiday, and the second one is not :

3/4 × 60/239 (remember : "and" relation)

= 3 × 15/239 = 45/239 = 0.188284519...

the first one is not on holiday, and the second one is :

60/240 × 180/239 = 1/4 × 180/239 = 45/239 =

= 0.188284519...

since there is no overlap of the potential events (there is no event that could be in both cases), this is an exclusive or relation, and we can add the probabilities.

so, the probability for exactly one of the picked passengers to be on holiday is

2×0.188284519... = 0.376569038... ≈ 0.3766

8 0
2 years ago
This equation shows how the total cost of visiting the art museum as a member is related to the number of visits. C = 9.2v + 21.
liubo4ka [24]

Answer:

6

Step-by-step explanation:

C=9.2v + 21.2

76.4 = 9.2v + 21.2

76.4 - 21.2 = 9.2v

55.2 = 9.2v

v= 55.2 / 9.2 = 6

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2 years ago
How do you convert from a radical expression to a rational exponent?
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30,60,90,120
40,80,120

they will both " ash " in 120 seconds (thats 2 minutes)...so they will both ash at 
10:42 a.m.
8 0
3 years ago
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