Answer:
15% = $5100
7% = 900
Step-by-step explanation:
With simultaneous equations we can take the easier number like numbers that end in 0 or 5 or 2 etc.
We have 7% which is a prime and 15 so we call and name 'x' = amount
invested at 15%
x = the amount invested at 15%
Then 6000-x = the amount invested at 7%
The total interest earned is $710.
Therefore solve the simultaneous equation by substituting the 6000-x
0.15x + 0.08 (6000-x) = 710
Solve for x:
0.15x - 0.07x + 353 = 780 -> x = 357/0.07= $5100
Therefore the amount invested at 7% interest = 6000 - 5100 = $900
and here, 6000-900 = 5100 = 15%
a) We have that the discount is 65 %
Scott buys a jacket for $150
First, we will calculate the discount
then we need to subtract the quantity calculated above from the original price
After the markdown Scott paid $52.5
b.
In order to know the taxes first, we need to calculate the 5% of $52.5
then we will sum the 5% plus the price after the markdown
The total cost of the jacket is $55.125
Answer:
The expected cost of the company for a 3000 tires batch is $120255
Step-by-step explanation:
Recall that given a probability of defective tires p, we can model the number of defective tires as a binomial random variable. For 3000 tires, if we have a probability p of having a defective tire, the expected number of defective tires is 3000p.
Let X be the number of defective tires. We can use the total expectation theorem, as follows: if there are events that partition the whole sample space, and we have a random variable X over the sample space, then
.
So, in this case, we have the following
.
Let Y be the number non defective tires. then X+Y = 3000. So Y = 3000-X. Then E(Y) = 3000-E(X). Then, E(Y) = 2949.
Finally, note that the cost of the batch would be 40Y+45X. Then
Answer:
I think this is how you use it.
Use the side lengths to classify the triangle as acute, right, or obtuse. Classify the triangle as acute, right, or obtuse. Compare the square of the length of the longest side with the sum of the squares of the lengths of the two shorter sides. Compare c2 with a2 b2.