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ASHA 777 [7]
3 years ago
11

Classify the following triangle. Check all that apply.

Mathematics
2 answers:
11Alexandr11 [23.1K]3 years ago
7 0
That is an isosceles right triangle.  (Also known as a 45 45 90 triangle).


skad [1K]3 years ago
6 0
A. Not equilateral because not all sides are the same
B. Not obtuse because no angles are more than 90 degrees.
C. Not acute because not all 3 angles in the triangle are less than 90 degrees
D. Yes it's a right triangle because one angle is 90 degrees (the square on the triangle shows it's 90 degrees)
E. Yes it's isosceles because two sides are the same.
F. No it's not scalene because scalene means all sides are unequal, but the picture shows two sides are equal.
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Answer:

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Step-by-step explanation:

aₙ = 1/2 x aₙ₋₁     n≥2  

a₁ = 64

a₂ = 1/2 x 64 = 32

a₃ = 1/2 x 32 = 16

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Find the solution set of this inequality|10x+20| ≤10
Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

|10x+20|\leq 10

Firstly, we will find critical values

so, let's assume it is equal

|10x+20|= 10

now, we can break absolute sign

For |10x+20|= -(10x+20):

-(10x+20)= 10

we can solve for x

-10x-20= 10

Add both sides by 20

-10x-20+20= 10+20

-10x= 30

Divide both sides by -10

and we get

x=-3

For |10x+20|= (10x+20):

(10x+20)= 10

we can solve for x

10x+20= 10

Subtract both sides by 20

10x+20-20= 10-20

10x= -10

Divide both sides by 10

and we get

x=-1

so, critical values are

x=-3

x=-1

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For (-\infty,-3):

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

|10\times -5+20|\leq 10

|-50+20|\leq 10

30\leq 10

so, this is FALSE

For [-3,-1]:

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

|10\times -2+20|\leq 10

|-20+20|\leq 10

0\leq 10

so, this is TRUE

For (-1,\infty):

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

|10\times 0+20|\leq 10

|0+20|\leq 10

20\leq 10

so, this is FALSE

so, solution is

[-3,-1]

7 0
3 years ago
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