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dybincka [34]
3 years ago
12

select all of the statements that are true for the given parabola?check all that apply(everything in picture)

Mathematics
1 answer:
Ivanshal [37]3 years ago
3 0
Its A or it could also be D

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A fair 20-sided die is tossed. What is the probability that the numbers 15 or 4 or 18 are tossed?
andrew11 [14]

The probability of 1 number showing up out of 20 is 1/20

The probability of 3 different numbers showing up would be 3/20

Answer: 3/20

7 0
2 years ago
Mandy and Pete have a biased spinner numbered 1, 2, 3, 4, 5. They each want to find an estimate for the probability that the spi
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Answer:

Pete

Step-by-step explanation:

Given that:

Mandy's Estimate :

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Pete's Estimate:

Number of spins, n = 200

A good probability estimate is one which has narrow margin of error with a high degree of confidence. These two variables are affected by sample size.

A high sample size give a narrower margin of error and increases the confidence level probability

Based on the sample size used by each of Pete and Mandy, we can conclude that, Pete's probability estimate would be better due to its significantly higher sample size.

5 0
3 years ago
At a high school, students can choose between three art electives, four history electives, and five computer electives. Each stu
V125BC [204]

Answer:

\frac{^3C_1\times ^4C_1}{^{12}C_2}

Step-by-step explanation:

Given,

Art electives = 3,

History electives = 4,

Computer electives = 5,

Total number of electives = 3 + 4 + 5 = 12,

Since, if a student chooses an art elective and a history elective,

So, the total combination of choosing an art elective and a history elective = ^3C_1\times ^4C_1

Also, the total combination of choosing any 2 subjects out of 12 subjects = ^{12}C_2

Hence, the probability that a student chooses an art elective and a history elective = \frac{\text{Total combination of choosing an art elective and a history}}{\text{ Total combination of choosing any 2 subjects}}

=\frac{^3C_1\times ^4C_1}{^{12}C_2}

Which is the required expression.

3 0
3 years ago
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Please simplify this equation​
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