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2 years ago

What is the simple interest on 500 for 5 years at the rate of 5% per annum

Mathematics

2 answers:

shepuryov [24]2 years ago

3 0

Answer:

125

Step-by-step explanation:

Formula Simple interest:

P x r x t

jeka942 years ago

3 0

I = principal x rate x time
I = 500 x .05 x 5
I = 125

( time is always expressed in years and you convert rate to a decimal )

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zubka84 [21]

Answer:

C) The scale factor is 2

Step-by-step explanation:

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2 years ago

Explain the steps for dividing decimals. Write three or four sentences.

ryzh [129]

Answer:

1.First Move the decimal point in the divisor and dividend.

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3.Divide as usual, being careful to line up the quotient properly so that the decimal point falls into place.

Step-by-step explanation:

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2 years ago

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Mike is three years older than his wife Karen.

kkurt [141]

Answer:

1. Karen= g^5 (not sure)
2. Mike = g^5 + 3 (not sure)

3. Karen = 25

Mike = 28

4. Karen = 35

Mike = 38

Step-by-step explanation:

1. if george age was g

karen age= g x 5 = g5

2. mike age= gx5 + 3

3. g = 5

karen age= 5 x 5 = 25

mike 25 + 3

4. g = 7

karen = 7x5 = 35

mike = 35 + 3

(i dont know if this correct or not but it my opinion)

8 0

2 years ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

kompoz [17]

$f_{X,Y,Z}(x,y,z)=\begin{cases}Ce^{-(0.5x+0.2y+0.1z)}&\text{for }x\ge0,y\ge0,z\ge0\\0&\text{otherwise}\end{cases}$

is a proper joint density function if, over its support, $f$ is non-negative and the integral of $f$ is 1. The first condition is easily met as long as $C\ge0$ . To meet the second condition, we require

$\displaystyle\int_0^\infty\int_0^\infty\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=100C=1\implies \boxed{C=0.01}$

b. Find the marginal joint density of $X$ and $Y$ by integrating the joint density with respect to $z$ :

$f_{X,Y}(x,y)=\displaystyle\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dz=0.01e^{-(0.5x+0.2y)}\int_0^\infty e^{-0.1z}\,\mathrm dz$

$\implies f_{X,Y}(x,y)=\begin{cases}0.1e^{-(0.5x+0.2y)}&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}$

Then

$\displaystyle P(X\le1.375,Y\le1.5)=\int_0^{1.5}\int_0^{1.375}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy$

$\approx\boxed{0.12886}$

c. This probability can be found by simply integrating the joint density:

$\displaystyle P(X\le1.375,Y\le1.5,Z\le1)=\int_0^1\int_0^{1.5}\int_0^{1.375}f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz$

$\approx\boxed{0.012262}$

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taurus [48]

What grade is this work for ?

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2 years ago

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