Answer:
V' = 20.2 V
Explanation:
The formula for the capacitance of a parallel plate capacitor, with air as a medium between the plates, is given by the following formula:
C = A∈₀/d
where,
V = Capacitance of capacitor
A = Area of plate
∈₀ = permittivity pf free space
d = distance between plates
Keeping all the other variables constant, the relationship between capacitance and the distance between plates is given as:
C α 1/d
Therefore, when the distance between plates is doubled, it implies that the capacitance of the capacitor becomes half. That is:
C' = C/2
Now the formula for capacitance of a capacitor, is also given as:
Q = CV
C = Q/V
where,
Q = charge stored in capacitor
V = Voltage across capacitor
Keeping the charge constant the relationship between capacitance and voltage is:
C α 1/V
Therefore, when the capacitance is halved, the voltage must be doubled, keeping the charge constant:
V' = 2V = (2)(10.1 V)
<u>V' = 20.2 V</u>
