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Aleks [24]
3 years ago
8

A ball rolls a hill with a constant acceleration of 3 m/s^2. how far did the ball move in that 4 s

Physics
1 answer:
USPshnik [31]3 years ago
3 0

Acceleration a = 3 ms²

time t =  4 s ,          

initial velocity  vi = 0  ( not given )  

Distance = s= ?                  

distance =s=            by using equation =     s= vit + 1/2 at²

                                                                       =  0*4 + 1/2 * 3*(4²)

                                                                      =  24m.

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Which type of light ray can produce identical but reversed
barxatty [35]

Answer: Identical rays are refracted upon entering

Explanation:

4 0
3 years ago
Read 2 more answers
You and your friends are driving down the road. Your car breaks down. You have to use a 1,210 N force to push the car 201 m to t
Katyanochek1 [597]

Answer:

2.43\cdot 10^5 J

Explanation:

Since the force applied is parallel to the displacement of the car, the work done on the car is simply given by:

W=Fd

where

F = 1210 N is the force applied on the car

d = 201 m is the displacement of the car

Substituting numbers into the equation, we find:

W=(1210 N)(201 m)=2.43\cdot 10^5 J

5 0
4 years ago
The terrarium is closed so Tai cannot add water to the plants however the plants have enough water Which of these best explains
slavikrds [6]

Answer:

because they have enough water

Explanation:

4 0
3 years ago
Please show work : A particle with mass 2.00 μg and a charge of – 200 nC has a velocity of 3000 m/s in the x-direction. There is
irga5000 [103]

Answer:

 x =4.5 10⁴ m

Explanation:

To find the distance that the particle moves we must use the equations of motion in one dimension and to find the acceleration of the particle we will use Newton's second law

     m = 2.00 mg (1 g / 1000 ug) (1 Kg / 1000g) = 2.00 10-6 Kg

     q = -200 nc (1C / 10 9 nC) = -200 10-9 C

Let's calculate the acceleration

     F = ma

     F = q E

     a = qE / m

     a = -200 10⁻⁹ 1000 / 2.00 10⁻⁶

     a = 1 10² m / s²

Let's use kinematics to find the distance traveled before stopping, where it has zero speed (Vf = 0)

     Vf² = Vo² -2 a x

     0 = Vo² - 2 a x

     x = Vo² / 2a

     x = 3000²/ 2100

     x =4.5 10⁴ m

This is the distance the particule stop, after this distance in the field accelerates in the opposite direction of the initial

Second part

In this case Newton's second law is applied on the y axis

      F -W = 0

      F = w = mg

      E q = mg

      E = mg / q

      E = 2.00 10⁻⁶ 9.8 / 200 10⁻⁹

      E = 9.8 10⁵ C

       

The direction of the field is such that the force on the particle is up, as the particle has a negative charge, the field must be directed downwards F = qE = (-q) E

7 0
4 years ago
If you know that the period of a pendulum is 1.87 seconds, what is the length of that pendulum? (assume that we are on earth and
laiz [17]

The length of the pendulum is 0.087 m. Option d is correct.

<h3>What is Simple harmonic motion?</h3>

Simple harmonic motion is periodic motion caused by a restoring force that is proportionate to the deviation from equilibrium.

Simple harmonic motion is periodic motion but many other conditions are dependent.

The time period of the pendulum is found as;

\rm T= 2 \pi \sqrt{\frac{L}{g} } \\\\ \rm 1.87 \ sec= 2 \times 3.14  \sqrt{\frac{L}{9.81 m/s^2} } \\\\ L=0.087 \ m

The length of the pendulum is 0.087 m

Hence, option d is correct.

To learn more about the simple harmonic motion refer to the link;

brainly.com/question/17315536

#SPJ1

4 0
2 years ago
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