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const2013 [10]
2 years ago
6

An object is dropped from a height of 75.0 m above ground level. (a) determine the distance traveled during the first second.

Physics
1 answer:
barxatty [35]2 years ago
6 0

The relevant formula we can use in this case would be:

h = v0 t + 0.5 g t^2

where,

h = height or distance travelled

v0 = initial velocity = 0 since it was dropped

t = time = 1 seconds

g = 9.8 m/s^2

 

So calculating for height h:

h = 0 + 0.5 * 9.8 m/s^2 * (1 s)^2

<span>h = 4.9 meters</span>

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