To solve this problem we will apply Newton's second law and the principle of balancing Forces on the rope. Newton's second law allows us to define the weight of the mass, through the function

$F = ma\rightarrow F =mg$

Here,

m = mass

a = g = Gravitational acceleration

Replacing we have that the weight is

$W= (10kg)(9.8)$

$W = 98N$

Since the rope is taut and does not break, the net force on the rope will be zero.

$\sum F = 0$

$T-W = 0$

$T = W$

$T = 98N$

Therefore the tensile force in the rope is 98N

8 0

3 years ago

What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight?Use 1.67×

vazorg [7]

The electric force on the proton is:

F = Eq

F = electric force, E = electric field strength, q = proton charge

The gravitational force on the proton is:

F = mg

F = gravitational force, m = proton mass, g = gravitational acceleration

Since the electric force and gravitational force balance each other out, set their magnitudes equal to each other:

Eq = mg

Given values:

q = 1.60×10⁻¹⁹C, m = 1.67×10⁻²⁷kg, g = 9.81m/s²

Plug in and solve for E:

E(1.60×10⁻¹⁹) = 1.67×10⁻²⁷(9.81)

E = 1.02×10⁻⁷N/C

5 0

3 years ago