Nonpolar molecules are the result of unequal electron pair sharing. True or False

This problem is based on the whole idea of pressure but I’m having trouble on when the area circle formula is included.

Mice21 [21]

Answer:

6.23x10^6Pa

Explanation:

Data obtained from the question include:

F (force) = 490N

r (radius) = 0.005m

A (area of the circlular heel) =?

P (pressure) =.?

First, we'll begin by calculating the area of the circlular heel. This is illustrated below:

Area of circle = πr^2

Area = 22/7 x (0.00)^2

Area = 7.86x10^-5m^2

Pressure is simply force per unit area. It represented mathematically as

Pressure = Force /Area

Pressure = 490/7.86x10^-5

Pressure = 6.23x10^6N/m2

Recall: 1N/m2 = 1Pa

Therefore, 6.23x10^6N/m2 = 6.23x10^6Pa

Therefore, the woman exert a pressure of 6.23x10^6Pa on the floor

8 0

4 years ago

28 points

dem82 [27]

Answer: C. 1.64 x 10-3 m/s2

7 0

3 years ago

In a physics lab, Asha is given a 10.7 kg uniform rectangular plate with edge lengths 67.3 cm by 53.5 cm . Her lab instructor re

Leya [2.2K]

Answer:

$I=2.6363\ kg.m^2$

Explanation:

Given:

dimension of uniform plate, $(0.673\times 0.535)\ m^2$

mass of plate, $m=10.7\ kg$

Now we find the moment of inertia about the center of mass of the rectangular plate is given as:

$I_{cm}=\frac{1}{12} \times m(L^2+B^2)$

where:

$L=$ length of the plate

$B=$ breadth of the plate

$I_{cm}=\frac{1}{12} \times 10.7\times(0.673^2+0.535^2)$

$I_{cm}=0.6591\ kg.m^2$

We know that the center of mass of the rectangular plane is at its geometric center which is parallel to the desired axis XX' .

Now we find the distance between the center of mass and the corner:

$s=\frac{\sqrt{ (0.673^2+0.535^2)}}{2}$

$s=0.4299\ m$

Now using parallel axis theorem:

$I=I_{cm}+m.s^2$

$I=0.6591+10.7\times 0.4299^2$

$I=2.6363\ kg.m^2$

6 0

3 years ago

Pc13 is a compound used to make pesticides. A reaction requires that 96.7 kg of pc13 be raised from 31.7 degrees celcius to 69.2

siniylev [52]

Answer:

Energy required = 3169.34 Joules.

Explanation:

The quantity of energy (Q) required can be determined by;

Q = mcΔθ

Where: m is the mass, c is the specific heat and Δθ is the change in temperature.

But, m = 96.7 kg, c = 0.874 J/(kg $^{o} C$ ), $T_{2}$ = $69.2^{o}$ and $T_{1}$ = $31.7^{o}$ .

So that,

Q = mc( $T_{2}$ - $T_{1}$ )

= 96.7 x 0.874 x ( $69.2^{o}$ - $31.7^{o}$ )

= 96.7 x 0.874 x 37.5

= 3169.3425

Q = 3169.34

= 3.2 KJ

The amount of energy required is 3169.34 Joules.

8 0

3 years ago

How solar panels are effective for sprayers?

vichka [17]

Answer:

Solar pesticide sprayer can give less tariff or price in effective spraying. Solar energy is absorbed by the solar panel which contains photovoltaic cells. ... This converted energy utilizes to store the voltage in the DC battery and that battery further used for driving the spray pump.

Explanation:

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6 0

3 years ago