Answer:
-4, -3, -2, -1, 0
Step-by-step:
1st: 1/4(-8) - 2 = -4 = y
2nd: 1/4(-4) - 2 = -3 = y
3rd: 1/4(0) - 2 = -2 = y
4th: 1/4(4) - 2 = -1 = y
5th: 1/4(8) - 2 = 0 = y
Answer:
Total impedance in circuit = 8 - 2j ohms
Step-by-step explanation:
Given:
Circuit one = 1 + 3j ohms
Circuit two = 7 - 5j ohms
Find:
Total impedance in circuit
Computation:
Total impedance in circuit = Circuit one + Circuit two
Total impedance in circuit = 1 + 3j + 7 - 5j
Total impedance in circuit = 8 - 2j ohms
Answer:
10 = b
Step-by-step explanation:
Begin by expanding (x + 5)^2
(x + 5)(x + 5)
First: x*x = x^2
Outside: x * 5 (the last term which is a 5)
Inside: 5+ x
Last: 5*5 = 25
x^2 + 5x + 5x + 25
x^3 + 10x + 25
