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3 years ago

These triangles are NOT similar! Why not? Use calculations AND words to explain.

Mathematics

1 answer:

Charra [1.4K]3 years ago

4 0

Answer:

Similar triangles are (roughly speaking) triangles that have the same angles and the same ratio of the length of their sides

We can use ratios to show that the triangles are not similar

14:20 as a fraction is 14/20 as a decimal is 0.7

12:16 as a fraction is 12/16 as a decimal is 0.75

The side lengths are not the same proportion as shown by the different decimal, so the triangles are not similar

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(i) 3 (a + 5b) + a (a + 4) (ii) y (10 - y) + 3 (y - 2) (iii) 2 (8a - 5b) + 3 (5a - 12) (iv) 3 (y - 3) + ( 8 - 6y + x) (v) a (a -

AveGali [126]

Answer:

$3 (a + 5b) + a (a + 4) = a^2 + 7a + 15b$

$y (10 - y) + 3 (y - 2) = - y^2+13y - 6$

$2 (8a - 5b) + 3 (5a - 12) = 31a -10b - 36$

$3 (y - 3) + ( 8 - 6y + x) = -3y + x-1$

$a (a - 2b) + b (b + 2a - c) =a^2 + b^2 - bc$

$5 (x - y + z) + (4x + 3y) =9x - 2y +5z$

Step-by-step explanation:

Solving (i):

$3 (a + 5b) + a (a + 4)$

Open brackets

$3 (a + 5b) + a (a + 4) = 3a + 15b + a^2 + 4a$

Collect like terms

$3 (a + 5b) + a (a + 4) = a^2 + 4a+3a + 15b$

$3 (a + 5b) + a (a + 4) = a^2 + 7a + 15b$

Solving (ii)

$y (10 - y) + 3 (y - 2)$

Open bracket

$y (10 - y) + 3 (y - 2) = 10y - y^2 + 3y - 6$

Collect like terms

$y (10 - y) + 3 (y - 2) = - y^2+10y + 3y - 6$

$y (10 - y) + 3 (y - 2) = - y^2+13y - 6$

Solving (iii)

$2 (8a - 5b) + 3 (5a - 12)$

Open bracket

$2 (8a - 5b) + 3 (5a - 12) = 16a -10b + 15a - 36$

Collect like terms

$2 (8a - 5b) + 3 (5a - 12) = 16a+ 15a -10b - 36$

$2 (8a - 5b) + 3 (5a - 12) = 31a -10b - 36$

Solving (iv)

$3 (y - 3) + ( 8 - 6y + x)$

Open bracket

$3 (y - 3) + ( 8 - 6y + x) = 3y - 9 + 8 - 6y + x$

Collect like terms

$3 (y - 3) + ( 8 - 6y + x) = 3y - 6y + x- 9 + 8$

$3 (y - 3) + ( 8 - 6y + x) = -3y + x-1$

Solving (v):

$a (a - 2b) + b (b + 2a - c)$

Open bracket

$a (a - 2b) + b (b + 2a - c) =a^2 - 2ab + b^2 + 2ab - bc$

Collect like terms

$a (a - 2b) + b (b + 2a - c) =a^2 + 2ab- 2ab + b^2 - bc$

$a (a - 2b) + b (b + 2a - c) =a^2 + b^2 - bc$

Solving (vi)

$5 (x - y + z) + (4x + 3y)$

Open brackets

$5 (x - y + z) + (4x + 3y) =5x - 5y +5z+4x +3y$

Collect like terms

$5 (x - y + z) + (4x + 3y) =5x +4x +3y- 5y +5z$

$5 (x - y + z) + (4x + 3y) =9x - 2y +5z$

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3 years ago

Inequality to Verbal

faltersainse [42]

Answer:

D. The range is greater than 25 and less than or equal to 31.

Step-by-step explanation:

y is range

≤ = less than or equal to

< = less than

5 0

3 years ago

Please help me understand

nalin [4]

Answer:

(x +2)(2x +1)

Step-by-step explanation:

The factors are the set of tiles down the left side: x + 1 + 1 = (x +2), and the set of tiles across the top: x + x + 1 = (2x +1)

Your factored form is shown in choice D:

(x +2)(2x +1)

_____

<em>Additional comment</em>

The point of this sort of diagram is to show you how the factors work together to give you the product. Each tile in the middle of the figure represents the product of the tile on the top line and the tile in the left column.

The product of x and x is x².

The product of 1 and x is x.

The product of 1 and 1 is 1.

The product of the two factors is the sum of all the tiles in the middle of the diagram: 2x² +5x +2.

3 0

2 years ago