You know from trigonometry that AB = 15 units, so the area of the larger triangle ACB is (1/2)*15*15 = 112.5 units^2.
Then the area of triangle ADE is
.. (112.5 -62.5) = 50 . . . . units^2
Answer:
Option B
Step-by-step explanation:
A unit circle means radius of the circle = 1 unit
Let a terminal point on the circle is (x, y) and angle between the point P and x-axis is θ.
Center of the circle is origin (0, 0).
Therefore, ordered pair representing the terminal point will be (OP×Cosθ, OP×Sinθ) = 
OP.Cosθ = 1×Cosθ = 
Cosθ =
θ =
,
where n = integers
Similarly, OP×Sinθ = 1×Sinθ = -
Sinθ = -
θ =
,
where n = integer
Common value of θ will be, θ = 
Option B will be the answer.
The second one is the only equivalent equation. Simply plug in each variable in each equation. And compare!
The graph of g is one-fifth as steep as the graph of f.
The function g basically takes the inputs for f and multiplies them by one-fifth, which means the outputs are one-fifth times those of f. Multiplying by one-fifth makes something smaller (it's the same as dividing by five). It helps to visualize this relationship, so I've attache the graphs below.