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4 years ago

The starting materials in a chemical reaction are called

Chemistry

2 answers:

Wewaii [24]4 years ago

8 0

<h2>Hello!</h2>

The answer is: The starting materials in a chemical reaction are called reactants... or can be called reagents too.

The principal component in a chemical reaction are the reactants, after the reaction, we have the products and we could have reactants too (if they are not completed consumed).

For example, given the following reaction:

$2C2H6+7O2 = 4CO2 + 6H2O$

Reactants are: 2C2H6 and 7O2

Products are: 4CO2 and 6H2O

Have a nice day!

Irina-Kira [14]4 years ago

4 0

It’s called the reactants

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What causes water's low vapor pressure?

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4 years ago

Read 2 more answers

The questions are attached

Sladkaya [172]

Answer:

Explanation:

a) Balanced chemical equation:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

b) Mass of oxygen gas needed = ?

Mass of propane = 25 g

Solution:

Number of moles of propane = mass/molar mass

Number of moles = 25 g/ 44.1 g/mol

Number of moles = 0.57 mol

now we will compare the moles of oxygen and propane:

C₃H₈ : O₂

1 : 5

0.57 : 5/1×0.57 = 2.85 mol

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 2.85 mol × 32 g/mol

Mass = 91.2 g

c) water vapors produced = ?

Mass of propane = 25 g

Solution:

Number of moles of propane = mass/molar mass

Number of moles = 25 g/ 44.1 g/mol

Number of moles = 0.57 mol

now we will compare the moles of water and propane:

C₃H₈ : H₂O

1 : 4

0.57 : 4/1×0.57 = 2.28 mol

Mass of water vapors:

Mass = moles × molar mass

Mass = 2.28 mol × 18 g/mol

Mass = 41.0 g

mass of water vapors produced = 1.5 kg (1500 g)

Mass of propane reacted = ?

Solution:

Number of moles of water vapors:

Number of moles = mass/molar mass

Number of moles = 1500 g/ 18 g/mol

Number of moles = 83.33 mol

now we will compare the moles of water and propane.

H₂O : C₃H₈

4 : 1

83.3 : 1/4×83.3 = 20.8 mol

Mass of propane:

Mass = number of moles ×molar mass

Mass = 20.8 mol × 44.1 g/mol

Mass = 917 g

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3 years ago

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Nimfa-mama [501]

Answer:

The gas cloud must be very dense.Temperatures must exceed 14 million Kelvin

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4 years ago

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Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(IV) oxide:You add 40.7 g of M

Alex787 [66]

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(a)
1.2424 moles of HCl would react completely with 1.2424 x (1/4) = 0.3106 mole of MnO2, but there is more MnO2 present than that, so MnO2 is in excess and HCl is the limiting reactant.

(b)
(1.2424 mol HCl) x (1 mol Cl2 / 4 mol HCl) x (70.9064 g Cl2/mol) = 22.0 g Cl2

(c)
(77.7% of 22.0 g Cl2) = 17.1 g Cl2</span>

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3 years ago