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Nezavi [6.7K]
3 years ago
7

How many grams of H2SO4 do I need to use in order to produce 3.01 moles of water? consider the equation. _Ca(OH)2 + _H2SO4 = _Ca

SO4 + _H20​
Chemistry
1 answer:
NARA [144]3 years ago
3 0

Answer:

148 g H₂SO₄

General Formulas and Concepts:

<u>Chemistry - Stoichiometry</u>

  • Reading a Periodic Table
  • Balancing RxN's
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

RxN:   Ca(OH)₂ + H₂SO₄ → CaSO₄ + H₂O

Given:   3.01 moles H₂O

<u>Step 2: Balance RxN</u>

Ca(OH)₂ + H₂SO₄ → CaSO₄ + 2H₂O

  • Need the same amount of O's and H's on both sides

<u>Step 3: Define conversions</u>

Molar Mass of H - 1.01 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂SO₄ - 2(1.01) + 32.07 + 4(16.00) = 98.09 g/mol

<u>Step 4: Stoichiometry</u>

<u />3.01 \ mol \ H_2O(\frac{1 \ mol \ H_2SO_4}{2 \ mol \ H_2O} )(\frac{98.09 \ g \ H_2SO_4}{1 \ mol \ H_2SO_4} ) = 147.625 g H₂SO₄

<u>Step 5: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules.</em>

147.625 g H₂SO₄ ≈ 148 g H₂SO₄

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