Answer:
I think the answer is a ploynucleotides
I hope this helps
Question
What mass of Al₂O₃ form is produced if 25.00 g of aluminum (al) is reacted completely?, knowing the molar mass of Al₂O₃ is 102 g/mol?
Atomic mass of Al =27 and O = 16
The molar mass of Al₂O₃ = 102.
Mass of aluminium in 102 g of Al₂O₃ = 54 g
54 g Al => 102 g Al₂O₃
25g Al => x g Al₂O₃
x = 25*102/54 = 47.2 g Al₂O₃
To solve more questions on molar mass check here:
brainly.com/question/21334167
Answer:
Reduced, alkane
Explanation:
Wolf-Kishner reaction is a type of reduction reaction in which aldehydes and ketones are reduced to their corresponding alkane in the presence of a base.
This reaction occurs at high temperature.
Alkane formed has a same number of carbon as aldehyde and ketone.
If acetaldehyde undergoes a Wolf-Kishner reaction in the presence of base and heat, then ethane is formed. Nitrogen is formed as a byproduct.
Here, acetaldehyde is reduced to form ethane.
So, acetaldehyde undergoes a Wolf-Kishner reaction, which is the addition of hydrazine with subsequent addition of a base and heat. In this reaction, the aldehyde is reduced, resulting in alkane product.
Answer:
1. Na2SO4(aq)+C4H6BaO4(aq) --> BaSO4(s) + 2C2H3NaO2(aq)
2. 2Na^+1(aq) + SO4^-2(aq) + 4C^+4(aq) + 6H^+1(aq) + Ba^-2(aq) + 4O^-2(aq) --> BaSO4(s) + 2C^-4(aq) + 2H^+1(aq) + 3Na^+1(aq) + 2O^-2(aq)
3. Ba^+2(aq) + SO4^-2(aq) --> BaSO4(s)
Explanation:
