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Sever21 [200]
2 years ago
11

Write the linear equation that gives the rule for this table.

Mathematics
1 answer:
MAVERICK [17]2 years ago
4 0

Answer:

The linear equation that gives the rule for this table will be:

  • y=x+25

Step-by-step explanation:

Taking two points from the table

  • (2, 27)
  • (3, 28)

Finding the slope between two points

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(2,\:27\right),\:\left(x_2,\:y_2\right)=\left(3,\:28\right)

m=\frac{28-27}{3-2}

m=1

We know the slope-intercept form of linear equation is

y=mx+b

where m is the slope and b is the y-intercept

substituting the point (2, 27) and m=1 in the slope-intercept form to determine the y-intercept 'b'

y=mx+b

27 = 1(2)+b

27-2 = b

b = 25

Now, substituting m=1 and b=25 in the slope-intercept form to determine the linear equation

y=mx+b

y=1(x)+25

y=x+25

Thus, the linear equation that gives the rule for this table will be:

  • y=x+25
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Answer:

45 / 6

Step-by-step explanation:

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3 years ago
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How many sequences of 0s and 1s of length 19 are there that begin with a 0, end with a 0, contain no two consecutive 0s, and con
sladkih [1.3K]

65 sequences.

Lets solve the problem,

The last term is 0.

To form the first 18 terms, we must combine the following two sequences:

0-1 and 0-1-1

Any combination of these two sequences will yield a valid case in which no two 0's and no three 1's are adjacent

So we will combine identical 2-term sequences with identical 3-term sequences to yield a total of 18 terms, we get:

2x + 3y = 18

Case 1: x=9 and y=0

Number of ways to arrange 9 identical 2-term sequences = 1

Case 2: x=6 and y=2

Number of ways to arrange 6 identical 2-term sequences and 2 identical 3-term sequences =8!6!2!=28=8!6!2!=28

Case 3: x=3 and y=4

Number of ways to arrange 3 identical 2-term sequences and 4 identical 3-term sequences =7!3!4!=35=7!3!4!=35

Case 4: x=0 and y=6

Number of ways to arrange 6 identical 3-term sequences = 1

Total ways = Case 1 + Case 2 + Case 3 + Case 4 = 1 + 28 + 35 + 1 = 65

Hence the number of sequences are 65.

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8 0
2 years ago
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Sphinxa [80]

The valid probability distributions are the ones in options C and D.

<h3>Which of the following are valid probability distributions?</h3>

For discrete random variables with probabilities p₁, p₂, ..., pₙ, there are two rules:

  • All of these probabilities are numbers between 0 and 1.
  • p₁ + p₂ + ... + pₙ = 1.

So, for the first rule we can discard the first option, where we have negative probabilities.

To check the other 4 options, just add the probabilities and see if the addition gives 1.

The options that add up to 1 are C and D, so these two are the correct options.

D: 1/5 + 1/10 + 1/10 + 1/10 + 1/5 + 1/10 + 1/10 + 1/10 = 1

C: 1/6 + 1/6 + 1/6 + 1/6 + 1/6 + 1/6 = 1

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3 0
1 year ago
Write the following equation in slope-intercept form 3x=-2y+4
Lorico [155]
The form is y=mx+b

3x=-2y+4 (add 2y)

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Answer:

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