Answer:
45 / 6
Step-by-step explanation:
65 sequences.
Lets solve the problem,
The last term is 0.
To form the first 18 terms, we must combine the following two sequences:
0-1 and 0-1-1
Any combination of these two sequences will yield a valid case in which no two 0's and no three 1's are adjacent
So we will combine identical 2-term sequences with identical 3-term sequences to yield a total of 18 terms, we get:
2x + 3y = 18
Case 1: x=9 and y=0
Number of ways to arrange 9 identical 2-term sequences = 1
Case 2: x=6 and y=2
Number of ways to arrange 6 identical 2-term sequences and 2 identical 3-term sequences =8!6!2!=28=8!6!2!=28
Case 3: x=3 and y=4
Number of ways to arrange 3 identical 2-term sequences and 4 identical 3-term sequences =7!3!4!=35=7!3!4!=35
Case 4: x=0 and y=6
Number of ways to arrange 6 identical 3-term sequences = 1
Total ways = Case 1 + Case 2 + Case 3 + Case 4 = 1 + 28 + 35 + 1 = 65
Hence the number of sequences are 65.
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The valid probability distributions are the ones in options C and D.
<h3>
Which of the following are valid probability distributions?</h3>
For discrete random variables with probabilities p₁, p₂, ..., pₙ, there are two rules:
- All of these probabilities are numbers between 0 and 1.
- p₁ + p₂ + ... + pₙ = 1.
So, for the first rule we can discard the first option, where we have negative probabilities.
To check the other 4 options, just add the probabilities and see if the addition gives 1.
The options that add up to 1 are C and D, so these two are the correct options.
D: 1/5 + 1/10 + 1/10 + 1/10 + 1/5 + 1/10 + 1/10 + 1/10 = 1
C: 1/6 + 1/6 + 1/6 + 1/6 + 1/6 + 1/6 = 1
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The form is y=mx+b
3x=-2y+4 (add 2y)
3x+2y=4 (subtract 3x)
2y=-3x+4 (divide by 2)
y= -2/3x+2
Answer:
81
Step-by-step explanation: