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s2008m [1.1K]
3 years ago
8

1. What is the sum of the two vectors (-1,-4) and (3,5)?

Mathematics
1 answer:
mash [69]3 years ago
8 0

What is the sum of the two vectors (-1,-4) and (3,5)

to find the sum we add x component with x and y with y

So

(-1+3) , ( -4+5) = (2,1)

Hence option B is the correct option


2. Evaluate the following expression: -1(5,-1) + 2(1,1)

-1(5,-1) + 2(1,1) = (-5 , 1) + (2,2)

= ( -3 , 3)

Second option is the correct


3. Evaluate the following expression (1,4) -5(1,1)

(1,4) -5(1,1)

= (1,4) (-5,-5)

= (1-5 , 4-5)

= (-4,-1)


4. Let v=(8,-4) and w=(-4,2). Which of the following is true?

as we can see

(8,-4) = -2(-4,2)

v= -2w

and also the Y component of w is 2


5. Which of the following vectors are orthogonal to (-1,3)?

The orthogonal vector will be (3,1) as the dot product is zero

(-1,3).(3,1) = (-3+3) = 0

Hence Option third is the correct one

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Answer:

Step-by-step explanation:

the answer is 3/7 ‍

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Which point lies on the graph of f(x) = -2(x + 3) – 5
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3 years ago
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In a competition, a school awarded medals in different categiories.40 medals in sport 25 medals in danceand 212 medals in music,
aleksley [76]

Answer:

210

Step-by-step explanation:

Given:

Medals in sports = 40

Medals in dance = 25

Medals in music = 212

Total students that received medals = 55

Total students that received medals in all three categories = 6

Required:

How many students get medals in exactly two of these categories?

Take the following:

A = set of persons who got medals in sports.

B = set of persons who got medals in dance

C = set of persons who got medals in music.

Therefore,

n(A) = 40

n(B) = 25

n(C) = 212

n(A∪B∪C)= 55

n(A∩B∩C)= 6

To find how many students get medals in exactly two of these categories, we have:

n(A∩B) + n(B∩C) + n(A∩C) −3*n(A∩B∩C)

=n(A∩B) + n(B∩C) + n(A∩C) −3*6 ……............... (1)

n(A∪B∪C)=n(A)+n(B)+n(C)−n(A∩B)−n(B∩C)−n(A∩C)+n(A∩B∩C)

Thus, n(A∩B)+n(B∩C)+n(A∩C)=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)

Using equation 1:

=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)−18

Substitute values in the equation:

= 40 + 25 + 212 + 6 − 55 − 18

= 283 - 73

= 210

Number of students that get medals in exactly two of these categories are 210

6 0
3 years ago
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