Question

Before a chair manufacturer sells its beanbag chairs, they spot check a random sample of chairs on the production line. The table below shows the number of common problems found during one such spot check. Common Problems Frequency Open seam 4 Cuts in upholstery 14 Understuffed 15 None 267 Total 300 If the manufacturer makes 1500 beanbag chairs per day, how many of those chairs would they expect to be understuffed?

Answer 1

Answer:

They would expect 75 chairs to be understuffed.

Step-by-step explanation:

Answer 2

Answer:

75

Step-by-step explanation:

Given :   In beanbags

             4 Cuts in upholstery

            15 are Understuffed  

             None 267

            Total 300

To Find : If the manufacturer makes 1500 beanbag chairs per day, how many of those chairs would they expect to be understuffed?

Solution :

We are given that out of total of 300 bags there are 15 understuffed

Let x be the no. of understuffed bean bags out of total of 1500.

⇒$\frac{15}{300} =\frac{x}{1500}$

⇒$\frac{15*1500}{300} =x$

⇒$75=x$

Thus  If the manufacturer makes 1500 beanbag chairs per day, 75 of those chairs would they expect to be understuffed .