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saveliy_v [14]
3 years ago
14

Which is the quotient of 5 ÷ 1/4 ? Use the model to help. due TOMMOROW help

Mathematics
1 answer:
DaniilM [7]3 years ago
6 0

The answer would be 1.25.

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if you purchase 5 shirt whitch are on sale for 17.98$ each write a expression for the total cost if the shirts
OLga [1]
5•17.98=89.9

$89.9 is needed
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Triangle L M Q is cut by perpendicular bisector L N. Angle N L Q is 32 degrees and angle L M N is 58 degrees.
Serga [27]

Answer:

Yes

Step-by-step explanation:

ΔMNL ≅ ΔQNL  by ASA or AAS

by ASA

Proof:

∠ LNM = ∠LNQ    =90

LN = LN   {Common}

∠MLN = ∠QLN     {LN bisects ∠ L}

By AAS

∠Q + ∠QLN + ∠LNQ = 180  {Angle sum property of triangle}

∠Q + 32 + 90 = 180

∠Q  + 122 = 180

∠Q = 180 -122 =

∠Q = 58

∠Q = ∠M

∠MNL =∠QNL = 90

LN = LN {common side}

8 0
3 years ago
What is 442.1 × 11 =​
Marta_Voda [28]

Answer: 4,863.1

Step-by-step explanation:

7 0
3 years ago
Consider the given geometric sequence.
Gala2k [10]
F5=(256)f1=16 hope this helps
7 0
3 years ago
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Find x(3x+72) triangle
Alinara [238K]

Answer: x = -4 ; Angle = 60°

Concept:

The given figure is a triangle with 3 arc signs on each angle. This <u>arc sign </u>stands for the corresponding angles are congruent, which in this question, it shows that all three angles are congruent. Sometimes, if the figure has multiple angles and there are different groupings of congruent angles, then we use different numbers of arcs or symbols.

Solve:

<u>Given information</u>

An angle = 3x + 72

Total measure of angles = 180 (triangle angle sum theorem)

Total number of congruent angles = 3

<u>Given expression</u>

Total measure = Total number of congruent angles × An angle measure

<u>Substitute values into the expression</u>

180 = 3 (3x + 72)

<u>Divide 3 on both sides</u>

180 / 3 = 3 (3x + 72) / 3

60 = 3x + 72

<u>Subtract 72 on both sides</u>

60 - 72 = 3x + 72 - 72

-12 = 3x

<u>Divide 3 on both sides</u>

-12 / 3 = 3x / 3

\boxed{x=-4}

<u />

<u>Find the angle measure</u>

3x + 72 = 3 (-4) + 72 = \boxed{60}

Hope this helps!! :)

Please let me know if you have any questions

6 0
2 years ago
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