Part b if you had a high-energy xenon particle beam and wanted to make gold, what element would you bombard? ? +143 54xe→197 79a
1 answer:
Answer:
The missing reactant is 55/25Mn
Explanation:
asumming the missing reagent is A/Z X
In nuclear reaction , the sum of atomic number and mass number of on both sides musst be equal
Thus ,
Z + 54 = 79 + 0
Z = 25
The element with atomic number 25 is Mn
A + 143 = 197 +1
A = 55
Therefore, the missing reagent is 55/25Mn
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Explanation:
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I attached a table of SI measurements for you :)
Hope this helped!
I attached a table of SI measurements for you :)
Hope this helped!