Question

Part b if you had a high-energy xenon particle beam and wanted to make gold, what element would you bombard? ? +143 54xe→197 79au+10n express your answer as an element symbol including subscripts and superscripts. view available hint(s) ? = submit

Answer 1

Answer:

The missing reactant is $Mn^{55} _{25}$  55/25Mn

Explanation:

asumming the missing reagent is A/Z X

In nuclear reaction , the sum of atomic number and mass number of on both sides musst be equal

Thus ,

Z + 54 = 79 + 0

Z = 25

The element with atomic number 25 is Mn

A + 143 = 197 +1

A = 55

Therefore, the missing reagent is 55/25Mn