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Artemon [7]
3 years ago
7

Part b if you had a high-energy xenon particle beam and wanted to make gold, what element would you bombard? ? +143 54xe→197 79a

u+10n express your answer as an element symbol including subscripts and superscripts. view available hint(s) ? = submit
Chemistry
1 answer:
Kaylis [27]3 years ago
7 0

Answer:

The missing reactant is Mn^{55} _{25}  55/25Mn

Explanation:

asumming the missing reagent is A/Z X

In nuclear reaction , the sum of atomic number and mass number of on both sides musst be equal

Thus ,

Z + 54 = 79 + 0

Z = 25

The element with atomic number 25 is Mn

A + 143 = 197 +1

A = 55

Therefore, the missing reagent is 55/25Mn

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